Answer:
51
Step-by-step explanation:
so we can use the variable x for minutes & y for water level. (4,17) is what we start with. its asking after 12 minutes what is the water level, 4 x 3 is 12 so we would multiply 17 x 3 as well which is 51.
A parabola that passes through the point (8, 28) has vertex (-2, 8). Its line of symmetry is parallel to the y-
axis.
Find equation of the parabola: y =
When x 18, what is the value of y:
What is the average rate of change between x = -2 and x = 18:
The equation of the parabola is y = 1/5( x + 2 )² + 8.
When x = 18 the value of y is 88 and the average rate of change between x = - 2 and x = 18 is 4.
The general equation of the parabola is given as:
y = a(x – h)² + k where ( h, k ) is the vertex of the parabola.
We have, the vertex as ( - 2, 8 ) and the parabola passes through ( 8, 28 ).
Then,
y = a(x – h)² + k
28 = a( 8 - (-2) )² + 8
28 = a(10)² + 8
28 - 8 = a(10)²
100a = 20
a = 20/100 = 1/5
Therefore, the equation of the parabola will be:
y = a(x – h)² + k
y = 1/5( x + 2 )² + 8
Now, when x = 18:
y = 1/5( x + 2 )² + 8
y = 1/5( 18 + 2 )² + 8
y = 1/5( 20 )² + 8
y = 80 + 8 = 88
Now, the change between x = - 2 and x = 18:
Then,
y = f(18) = y = 1/5( 18 + 2 )² + 8 = 1/5(20)² + 8 = 88
And;
y = f( - 2) = 1/5( -2 + 2 )² + 8 = 1/5(0)² + 8 = 8
Therefore the average rate of change between x = - 2 and x = 18 will be:
= [ f(18) - f(-2) / ( 18 - (-2) ) ]
= ( 88 - 8 ) / 20
= 80/20
= 4
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(Combining Equations)What is the result of subtracting the second equation from the first ? -4x - 2y = -2x - 2y = 9
Subtract the second equation from the first,
[tex]\begin{gathered} -4x-2y=-2 \\ - \\ x-2y=9 \\ (-4x-x)-(2y-\lbrack-2y\rbrack)=-2-9 \\ -5x-2y+2y=-11 \\ -5x+0=-11 \\ -5x=-11 \\ \text{Divide both sides by -5} \\ \frac{-5x}{-5}=\frac{-11}{-5} \\ x=\frac{11}{5} \end{gathered}[/tex]solve the following system of equations-5x-3y=-16-3x+2y=-21x=y=
-5x - 3y = -16
-3x + 2y = -21
Solving for y the first equation:
-5x + 16 = 3y
y = (-5/3)x + (16/3)
Using this value of y into the second equation:
-3x + 2(-5/3)x + 2(16/3) = -21
-3x - (10/3)x + 32/3 = -21
Multiplying all by 3:
-9x - 10x + 32 = -63
-19x = -63 - 32 = -95
x = 95/19
Using this value of x into the y we found with the first equation:
y = (-5/3)x + 16/3
y = (-5/3)(95/19) + 16/3 = -475/57+ 304/57 = -171/57
y = -171/57
x = -31/19 = -1.6315
y = -171/57 = -3
Answer:
x = -1.6315
y = -3
Kindly assist in answering these questions
The point of origin on the graph is (0,0) and the constant of proportionality is equal to 3.
Equation of LineThe equation of a straight line is y=mx + c. y = m x + c m is the gradient and c is the height at which the line crosses the y -axis, also known as the y -intercept.
The equation of line is an algebraic form of representing the set of points, which together form a line in a coordinate system. The numerous points which together form a line in the coordinate axis are represented as a set of variables x, y to form an algebraic equation, which is referred to as an equation of a line.
In the given question, we are asked to find several values relating to the graph attached.
5) The point of origin on the graph is at (0,0) because the graph passes through the center along the straight line.
6) The constant of proportionality (k) is the value before the variable x.
The equation of the line is y = 3x.
The constant of proportionality of the equation is equal to 3.
7) The value of the ratio k is given as y/x
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Evaluate when n=5 4n
We are given an expression "4n"
The question says to evaluate this expression when n = 5
Here, evaluation simply means, finding the value of "4n" when n = 5. This is a simple problem of substitution. By substitution I mean replacing every occurence of n in the given expression by 5. This would be done as follows:
Given expression = 4n
Note that here 4 is being multiplied to n.
Replacing n by 5, we get the result as:
[tex]4\text{ }\times\text{ 5 = 20 }[/tex]From here, we can conclude that the value of expression "4n" for n = 5 will be 20.
7. Julie has $250 to plan a party. There is a one-time fee of $175 to reserve a room. It also cost $1.25 perperson for food and drinks. What is the maximum number of people that can come to the dance?
Julie has $250 to plan the party.
The room costs $175 to reserve plus $1.25 per person for food and drinks.
Let "x" represent the number of people she can invite, you can express the total cost for the party as follows:
[tex]175+1.25x\leq250[/tex]From this expression, we can determine the number of people she can invite, without exceeding the $250 budget.
The first step is to pass 175 to the right side of the expression by applying the opposite operation "-175" to both sides of it:
[tex]\begin{gathered} 175-175+1.25x\leq250-175 \\ 1.25x\leq75 \end{gathered}[/tex]Next, divide both sides of the equation by 1.25 to reach the value of x:
[tex]\begin{gathered} \frac{1.25x}{1.25}\leq\frac{75}{1.25} \\ x\leq60 \end{gathered}[/tex]She can invite up to 60 people to the party
A helicopter pilot sights a landmark an an angle of depression of 34°. The altitudeof the helicopter is 1,748 feet. To the nearest foot, what is the horizontal distancefrom the helicopter to the landmark?
For the question, we will be making a sketch showing the features in the question.
From the sketch and the question, the angle of depression = 34 degrees
The helicopter height above the ground (altitude) = 1,748 ft
L represents the landmark
x = horizontal distance from the helicopter to the landmark
To solve the question, we need to bring out the right triangle from the sketch
Angle e = 34 degrees (alternate to the angle of depression given)
To get x, we make use of the trigonometrical ratio of tan
[tex]\begin{gathered} \tan \text{ }\theta=\frac{opposite}{adjacent} \\ \text{From the right triangle, the opposite = 1748} \\ \text{The adjacent = x} \\ \theta=34^0 \\ \tan \text{ 34 =}\frac{\text{1748}}{x} \\ \text{Making x the subject of the formula, we have} \\ x=\frac{1748}{\tan 34} \\ x=\frac{1748}{0.6745} \\ x=2591.55 \end{gathered}[/tex]Therefore, the horizontal distance from the helicopter to the landmark to the nearest foot is 2592 feet.
$3.44 at the Farmers market at a grocery store the same oranges cost $8.40 for a bag of 20 find the better deal by calculating the unit rate for both locations how much would be saved per orange by purchasing oranges at the locations with the better deal solve the word problemFarmers market unit rate --------------grocery store unit rate ------------------better deal -------------how much is saved ------------A $0.01/ orangeslB $0.41 / orangeC grocery storeD Farmers marketE $0.43 / orangeF $0.40 / OrangeG $0.10 / Orange
Given :
At the farmer market : a bag of 8 oranges cost $3.44
At the grocery store : a bag of 20 oranges cost $8.4
So, the unit rate at the farmer market = 3.44/8 = $0.43/ orange
And the unit rate at the grocery store = 8.4/20 = $0.42/ orange
So, the better deal is the grocery store
how much is saved ?
the saving = 0.43 - 0.42 = $0.01/ orange
Find a standard form of the equation for the circle with the following property
Solution:
Given:
[tex]Endpoints\text{ }(-7,5)\text{ and }(-5,-1)[/tex]To get the equation of the circle, the center of the circle and the radius are needed.
The center of the circle is the midpoint of the endpoints.
Using the midpoint formula;
[tex]\begin{gathered} M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}) \\ where: \\ x_1=-7,y_1=5 \\ x_2=-5,y_2=-1 \end{gathered}[/tex]Thus,
[tex]\begin{gathered} M=(\frac{-7+(-5)}{2},\frac{5+(-1)}{2}) \\ M=(\frac{-12}{2},\frac{4}{2}) \\ M=(-6,2) \end{gathered}[/tex]Hence, the coordinates of the center of the circle is (-6,2)
The length of the diameter can be gotten using the distance between two points formula;
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex][tex]\begin{gathered} where: \\ x_1=-7,y_1=5 \\ x_2=-5,y_2=-1 \\ Hence, \\ d=\sqrt{(-5-(-7))^2+(-1-5)^2} \\ d=\sqrt{2^2+(-6)^2} \\ d=\sqrt{4+36} \\ d=\sqrt{40} \end{gathered}[/tex]The diameter is twice the radius. Hence, the radius is;
[tex]\begin{gathered} r=\frac{d}{2} \\ r=\frac{\sqrt{40}}{2}=\frac{2\sqrt{10}}{2} \\ r=\sqrt{10} \end{gathered}[/tex]Hence, the equation of the circle with center (-6,2)
[tex]with\text{ radius }\sqrt{10}[/tex]Using the standard form of the equation of a circle;
[tex]\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ where: \\ (h,k)\text{ }is\text{ }the\text{ center} \\ r\text{ is the radius} \\ h=-6 \\ k=2 \\ r=\sqrt{10} \end{gathered}[/tex]Hence, the equation is;
[tex]\begin{gathered} (x-(-6))^2+(y-2)^2=(\sqrt{10})^2 \\ (x+6)^2+(y-2)^2=10 \end{gathered}[/tex]Therefore, the equation of the circle is;
[tex](x+6)^{2}+(y-2)^{2}=10[/tex]
Write a proportional that relates the corresponding sides. You must use all of the sides for both triangles in your statement.
Given
Answer
[tex]\Delta HGF\approx\Delta HKL[/tex]GF is proportional to KL
HG is proportional to HK
HF is proportional to HL
Una clase tiene 42 alumnos. Se puede determinar que 3/9 son niños y 4 6 son niñas, ¿Cuántos niños y cuantas niñas hay en la clase?
The number of boys and girls that are in this class is equal to 28 students and 14 students respectively.
How to determine the number of boys?In order to determine the number of boys that are in this class with a total population of 42 students, we would have to multiply the total number of students by the fraction representing only the number of boys as follows:
Number of boys, B = 4/6 × Total number of students
Substituting the given parameters into the formula, we have;
Number of boys, B = 4/6 × 42
Number of boys, B = 4 × 7
Number of boys, B = 28 students.
Similarly, we we would have to multiply the total number of students by the fraction representing only the number of girls as follows:
Number of girls, G = 3/9 × Total number of students
Number of girls, G = 3/9 × 42
Number of girls, G = 1/3 × 42
Number of girls, G = 42/3
Number of girls, G = 14 students.
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Complete Question:
A class has 42 students. It can be determined that 3/9 are boys and 4/6 are girls, how many boys and girls are there in the class?
A sample of 7 adult elephants had an average weight of 12,572 pounds. The standard deviation for the sample was 26 pounds. Find the 95% confidence interval of the population mean for the weights of adult elephants. Assume the variable is normally distributed. Round intermediate answers to at least three decimal places. Round your final answers to the nearest whole number.
Answer
[tex]CI=(12553<\mu<12591)[/tex]Explanation
The confidence interval formula is given by
[tex]\begin{gathered} CI=\bar{x}\pm z\frac{s}{\sqrt[]{n}} \\ \text{Where;} \\ CI\text{ is the 95 percent confidence interval} \\ \bar{x}\text{ is the average weight }=12572 \\ z\text{ is the confidence value }=1.96 \\ s\text{ is the sample standard deviation }=26 \\ n\text{ is the sample size }=7 \end{gathered}[/tex]This implies that
[tex]\begin{gathered} CI=12572\pm1.96(\frac{26}{\sqrt[]{7}}) \\ CI=12572\pm\frac{50.960}{2.646} \\ CI=12572\pm19.259 \\ CI=(12552.741,12591.259) \\ CI=(12553<\mu<12591) \end{gathered}[/tex]The 95% confidence interval of the population mean for the weights of adult elephants is (12553 < μ < 12591)
Find the slope of the lines (-3,-1) and (-6,-10)
m = rise/run = (-10 - (-1))/(-6 - (-3)) = -9/-3 = 3
the slope of the line is equal to 3.
What is the slope of this line?
Enter your answer as a whole number or a fraction in simplest form in the box.
Answer:
1/4
Step-by-step explanation:
you just look at rise over run from one point to another and simplify.
i need help please,solve and explain it's 4th grade math.. thank you.
What you can say about 12th, 18th and the 21st child, depends if these numbers are multiples of 4 (every 4th child is wearing spectacles), 3 (every 3rd child is a girl) and 2 (every 2nd child is wearing a white shirt).
If a numer is multiple of another one, then the quotient between them is an integer number.
for 12th:
12/4 = 3
12/3 = 4
12/2 = 6
12 is multiple of 3, 4 and 6.
Then, 12th child is wearing spectacles, a white shirt and is a girl.
for 18th:
18/4 = 4.5
18/3 = 6
18/2 = 9
18 is multiple of 3 and 2.
Then, 18th child is a girl and is weraing a white shirt
for 21th:
21/4 = 5.25
21/3 = 7
21/2 = 11.5
21 is multiple of 3.
THen, 21st child is a girl.
72, - 16, - 8, 40
[tex]72, - 16, - 8, 40[/tex]
The solution to the mathematical problem is using the mathematical operation of addition, getting the sum of the numbers as 88.
What is an addition operation?An addition operation is one of the four basic mathematical operations, including division, subtraction, and multiplication.
When a number is added to another, the result of the addition operation is a sum or the total.
Addition operations are classified into two or more addends, the plus symbol (+), the equal sign (=), and the sum.
72 + -16 + -8 + 40
Group additions and subtractions:
72 + 40 + -16 + -8
Simplify the operations:
= 112 - 24
Solution:
= 88
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Mr. Herman had $125, and Mr.Chandra had $80. After each of them had paid for a concert ticket, Mr. Herman had 6 times as much money as Mr. Chandra. how much money did Mr. Chandra have left?
We have
Let x = cost of the ticket
After paying for the tickets, Mr. Herman had 125 - x
and Mr Chandra had 80 - x
Then, the equation is:
[tex]125-x=6(80-x)[/tex]So, solve for x:
[tex]\begin{gathered} 125-x=480-6x \\ 125-x+6x=480-6x+6x \\ 125+5x=480 \\ 125+5x-125=480-125 \\ 5x=355 \\ \frac{5x}{5}=\frac{355}{5} \\ x=71 \end{gathered}[/tex]The concert ticket cost is $71
Therefore, Mr. Chandra have left:
[tex]80-71=9[/tex]Answer: $9
write an equation and solvefour times the complement of an angle is 40° lessthan twice the angles supplement. Find the angle,its complement, and its supplement
Let the angle be 'x' degrees.
The complement (C) of the corresponding angle will be,
[tex]C=90-x[/tex]And the supplement (S) of the corresponding angle will be,
[tex]S=180-x[/tex]According to the condition given in the problem,
[tex]4C=2S-40^{}[/tex]Substitute the values,
[tex]\begin{gathered} 4(90-x)=2(180-x)-40 \\ 360-4x=360-2x-40 \\ -4x=-2x-40 \\ 4x-2x=40 \end{gathered}[/tex]Simplify the expression further,
[tex]\begin{gathered} 2x=40 \\ x=\frac{40}{2} \\ x=20 \end{gathered}[/tex]Substitute this value of 'x' to obtain the complement and supplement angles as follows,
[tex]\begin{gathered} C=90-20=70 \\ S=180-20=160 \end{gathered}[/tex]Thus, the angle measures 20 degrees, its complement measures 70 degrees, while its supplement measures 160 degrees.
Find y if the line through (5, 1) and (6, y) has a slope of 3.
Answer:
Y = 32
Step-by-step explanation:
Y = mx + c, with a slope of 3
Y = 3x + c
Substitute values:
1 = 3 (5) + c
1 = 15 + c
c = -14
Rewrite formula:
Y = 3x - 14
Y = 3 (6) + 14
Y = 18 + 14
Y = 32
Hope this helps :)
Answer:
y = 4
Step-by-step explanation:
y = mx + b is the slope intercept form of a line.
We need an m (slope and a b(y-intercept)
They give us the slope, so we have to find the b
slope = 3
y = 1
x = 5
We need and x and y on the line and the point (5,1) gives us that.
y = mx + b
1 = 3(5) + b
1 = 15 + b Subtract 15 from both sides of the equation
-14 = b
Now we have the m (slope of 3) and the b (the y-intercept of -14)
y = mx + b
y = 3x -14 Now plug is the x (6) from the point given and solve for its y
y = 3(6) -14
y = 18 - 14
y = 4
find the zeros algebraically: f(x)=x^4-8x^3+5x^2+14x
The given equation is:
x^4-8x^3+5x^2+14x
In this question, we have to find the zeros algebraically. Hence, we need to find the values of x that satisfy the equation.
Note: The roots (values of x) are equal to the power of the equation. Therefore, the given equation will have 4 roots
Therefore,
x^4-8x^3+5x^2+14x = 0
or
x(x^3-8x^2+5x+14) = 0
=> x = 0 and x^3-8x^2+5x+14 = 0
Therefore, the first root is x = 0.
Now,
x^3-8x^2+5x+14 = 0
To simplify that, try putting different values of x (starting from 1 and -1). The value that makes both sides equal to zero would be the solution.
Let's start with (1):
For x = 1
(1)^3 - 8(1)^2 + 5(1) + 14 = 0
1 -8(1) + 5 + 14 = 0
-1 -8 +5 + 14 = 0
- 9 + 19 = 0
10 = 0
It is false, therefore, x = 1 is not the solution.
For x = -1
(-1)^3 - 8(-1)^2 + 5(-1) + 14 = 0
-1 -8(1) - 5 + 14 = 0
-1 -8 -5 + 14 = 0
- 14 + 14 = 0
0 = 0
hence, x = -1 is the second solution.
If x = -1 is the solution, (x + 1) should be the factor of x^3-8x^2+5x+14. Therefore, the whole equation can be divided by factor
x^3-8x^2+5x+14 / (x+1). = x^2 - 9x + 14. (using division)
Now, let's find the roots of x^2 - 9x + 14
x^2 - 9x + 14 = 0
x^2 - 7x - 2x + 14 = 0
x(x - 7) - 2 (x - 7) = 0
(x - 7) (x - 2) = 0
or
x - 7 = 0. and x - 2 = 0
x = 7 and x = 2
Therefore, the zeros of the given equation are, 0, -1, 2 and 7.
how to find a volume of a cylinder that has a radius of 10 and a base of 4 Khan academy
Question:
Find a volume of a cylinder:
Solution:
Remember that the volume of the cylinder with radius r and height h is given by the following formula:
[tex]V\text{ = }\pi r^2h[/tex]then, replacing the data of the problem into the previous equation, we get:
[tex]V\text{ = }\pi(4^2)(10)\text{ = 3.14 (16)(10) = 502.4}[/tex]thus, we can conclude that the correct answer is:
[tex]V\text{ = 502.4}[/tex]
A psychology test has personality questions numbered 1, 2, 3, intelligence questions numbered 1, 2, 3, 4, and attitudequestions numbered 1,2. If a single question is picked at random, what is the probability that the question is an intelligence question OR has an odd number?
Answer:
7/9.
Step-by-step explanation?
Total number of questions: 3 + 4 + 2 = 9.
Number of Intelligence questions: 4
Number of questions that have an odd number: 5
The probability of a question is Intelligence questions = 4/9
The probability a question has an odd number = 5/9
The probability a question is Intelligence questions and has an odd number = 2/9
The probability a question is Intelligence question OR has an odd number is:
4/9 + 5/9 - 2/9 = 7/9.
12. A high school principal wants to determine if students' mathematical reasoning ability has any impact on their membership in academic clubs at the school. Twenty students were selected and given a mathematical reasoning test, with scores ranging from o to 50 (higher scores indicate more mathematical reasoning ability). Students were motivated to do well on the test with a reward system. These same students' membership in academic clubs was verified. Identify the response variable. A. Mathematical reasoning ability B. The high school C. Mathematical reasoning test D. Membership in academic clubs
Response variable: The response variable is the subject of an experiment.
In this question:
The experiment is about the mathematical reasoning ability of the students whom are members of academic clubs. So, we are focusing on mathematical reasoning ability, which is the response variable.
The answer is option A
15. I need help on this question. How do you do it?
Solution:
Given the expression:
[tex]-5^2[/tex]This expression is evaluated as
[tex]\begin{gathered} -5\text{ multiplied in 2 places} \\ \Rightarrow-5\times-5 \\ =25 \end{gathered}[/tex]Hence,
[tex]-5^2[/tex]is evaluated to be 25
I need help me answering #10 I'm really bad with ratios. (also sorry for the bad lighting in the picture)
The ratio of Perch to total fish is:
3 ( Number of perch that he caught)
------------------------------------------------------
9 ( The result of the addition of all values)
Simplifying, we have:
1
---
3
So, the answer would be 1 : 3
Geometry Problem - Given: segment AB is congruent to segment AD and segment FC is perpendicular to segment BD. Conclusion: Triangle AEG is isosceles. (Reference diagram in picture)
As the triangle AEF has 2 angles with the same measure, triangle AEF is isosceles.
can some one clarify this question, i think ik the answer but i need some elses opinion Find m
hello
to solve this question, we simply need to add two quadrants that make up mto get m[tex]\begin{gathered} m<\text{WYV}=60^0 \\ m<\text{VYU}=85^0 \end{gathered}[/tex][tex]\begin{gathered} m<\text{WYU}=<\text{WYV}+m<\text{VYU} \\ m<\text{WYU}=60^0+85^0 \\ m<\text{WYU}=145^0 \end{gathered}[/tex]from the calculations above, the value of m
A normal distribution has a mean of 101 and a standard Deviation of 12. find the probability that a value selected at random is in the following interval.at most 13
Answer:
84.134%
Explanation:
First, determine the value of the z-score.
[tex]\begin{gathered} Z=\frac{X-\mu}{\sigma} \\ =\frac{113-101}{12} \\ =\frac{12}{12} \\ z-score=1 \end{gathered}[/tex]Next, we determine the probability that a value selected at random is at most 113:
[tex]\begin{gathered} P(X\le113)=P(x\le1)_{} \\ =0.84134 \\ =84.134\% \end{gathered}[/tex]Thus, the probability that a value selected at random is in the given interval is 84.134%.
hey there mr or ms could you please help me out here?
The two triangles have a common side, RQ.
Also, given the two sides (left and right) are equal.
Also, the angle between the two sides (one side given and bottom side) is given as 90 degrees.
Thus,
we have
2 sides AND 1 angle congruent in each triangle
That is:
Side-Angle-Side, which is
SAS
THe triangles are congruent according to SAS, option B
I need to double check 15 I got answer B
We will have that the area of one sector of the circle will be:
[tex]A=(\frac{45}{360})\pi(20in)^2\Rightarrow A=\frac{25\pi}{2}in^2[/tex]So, the solution is option B.
