Explanation:
Mole ratio of Zn to HCl = 1 : 2.
If we use all 2.0mol of Zn, we would need 2.0 * 2 = 4.0mol of HCl. However we only have 3.0mol of HCl.
Therefore HCl is limiting.
HURRY PKEASE HELP!!!
Answer: the last one
Explanation:
Arrange the electrons in the sulfur atom in the orbital diagram
Answer:
So since there are 16 electrons in sulfur and the first layer of electrons in an orbital shell has a max of two, the first layer will be full. The second layer has a max of 8, so that will also be full. The third layer also has a max of 8 but will not get filled up since there are only 6 electrons left. These are the valence electrons. The orbital diagram will usually look like this:
( O = nucleus, . o = electron)
o o
o O o o
o
What is the total number of valence electrons in an atom with the electron configuration 2-8-1 ?
A) 1
B) 2
C) 8
D) 11
Answer:
1 because the last one is 1 and the previous shell was complete.
Answer: A)1
Explanation:
Valence electrons are always in Thebes last shell and last number of the configuration.
Why it important not to mix the test solution in one well with the solution in another week on your spot plate
Depending on the factors, combining two chemicals that aren't designed to interact might result in an explosion, an unintended chemical reaction, or a misleading result.
What is explosion ?An explosion is a sudden increase in volume accompanied by a tremendous energy release that typically results in the production of high temperatures and the discharge of high-pressure gases. High explosive detonations produce supersonic explosions that move through shock waves.
Explosions often fall into one of three categories: chemical, mechanical, or nuclear. Every kind of explosion has the potential to be devastating and serious, wreaking unimaginable damage on the local populace, environment, and infrastructure.
What causes gamma ray bursts is one of the largest unsolved questions of all. These bursts, which happen around once every day, are the most powerful explosions known to science.
Thus, depending on the factors, combining two chemicals that aren't designed to interact might result in an explosion, an unintended chemical reaction.
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What is the atom of CO2
Answer:
Carbon dioxide is composed of one carbon atom covalently bonded to two oxygen atoms. It is a gas (at standard temperature and pressure) that is exhaled by animals and utilized by plants during photosynthesis. Carbon dioxide, CO2, is a chemical compound composed of two oxygen atoms and one carbon atom
Explanation:
Answer:
Carbon dioxide is composed of one carbon atom covalently bonded to two oxygen atoms. It is a gas (at standard temperature and pressure) that is exhaled by animals and utilized by plants during photosynthesis. Carbon dioxide, CO2, is a chemical compound composed of two oxygen atoms and one carbon atom.
Explanation:
hope this help
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What is Entropy of reaction?
Answer:
The entropy change in a chemical reaction is given by the sum of the entropies of the products minus the sum of the entropies of the reactants.
Explanation:
Hope it helps
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Which the following statement ia correct for the equation shown here
Calculate the number of joules needed to change the temperature of 40.0 g of water from 33.0 degree c to 43.0 degree c
Answer:
c
Explanation:
Match the functions with the corresponding cell structure.
Column A
1.
Cell Membrane:
Cell Membrane
2.
Nucleus:
Nucleus
3.
Cytoplasm:
Cytoplasm
Column B
a. Protect the DNA and genes required for protein synthesis
b. Enclose the components of the cell and Regulate passage of substances through the cell
c. Houses the major organelles such as the mitochondria that are essential for creating energy.
Answer:
1c 2a 3b
Explanation:
Answer:
1.C
2.A
3. B
Explanation:
How do other factors shape earths surface
Answer:
Other factors shape earths surface are:
Factors that Shape Earth's Surface.
Unit Notes.
Plate Tectonics. Continental Drift. ...
Results of plate movement. ...
Weathering. ...
Erosion and Deposition.
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The following reaction shows calcium chloride reacting with silver nitrate.
CaCl2 + 2AgNO3 → 2AgCl + Ca(NO3)2
How many grams of AgCl are produced from 30.0 grams of CaCl2?
(Molar mass of Ca = 40.078 g/mol, Cl = 35.453 g/mol, O = 15.999 g/mol, Ag = 107.868 g/mol, N = 14.007 g/mol)
A. 19.4 grams
B. 38.8 grams
C. 58.2 grams
D. 77.5 grams
Explanation:
Molar mass of CaCl2 = 110.98g/mol
Moles of CaCl2 = 30.0 / 110.98 = 0.270mol
Moles of AgCl = 0.270mol * 2 = 0.540mol
Mass of AgCl = 0.540mol * (143.32g/mol) = 77.39g.
Answer:
77.5
Explanation:
You gotta round.
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2. Use the picture below to answer the question. ** С D B Bob is riding a roller coaster. At vihat point does the car have the most potential energy? А A 3
Answer:
the answer is A
Explanation:
Answer:
a
Explanation:
the roller coaster is at the highes pont witch is a .
What volume in milliliters of 100 proof vodka (50% v/v ethanol) would be likely to kill a typical 360-g rat?
The given question is incomplete, the complete question is:
The LD50 value for ethyl alcohol given orally to rats is 10.3 g/kg. What volume in milliliters of 100 proof vodka (50% v/v ethanol) would be likely to kill a typical 360-g rat?
Answer:
The correct answer is 9.4 ml.
Explanation:
Based on the given information, in rats the LD50 of ethyl alcohol is 10.3 g/kg.
As 1 Kg is 1000 grams
Now the value of LD50 of ethyl alcohol in rats is 10.3 grams/ 1000 grams
The volume of the lethal dose of vodka for a 360 gram rat would be,
= 360 g × (10.3 g/1000 g)
= 3708 × 10⁻³ g
= 3.708 g
Now the volume of vodka can be determined by using the formula,
V = mass/density
The density of ethanol is 0.789 g/ml
The volume would be,
V = 3.708 g/0.789 g/ml
V = 4.70 ml
As 50 percent of Vodka is ethanol, the volume of vodka needed to kill a rat is,
= 2 × Volume of ethanol
= 2 × 4.70 g/ml
= 9.4 ml
Fe2O3(s) 2Al(s)Al2O3(s) 2Fe(s) Using standard absolute entropies at 298K, calculate the entropy change for the system when 1.73 moles of Fe2O3(s) react at standard conditions.
Answer:
[tex]\Delta S=54.3\frac{J}{K}[/tex]
Explanation:
Hello!
In this case, for the given reaction, we can write the equation to compute the entropy change as shown below:
[tex]\Delta s=2\Delta S_{Fe}+\Delta S_{Al_2O_3}-2\Delta S_{Al}-\Delta S_{Fe_2O_3}[/tex]
Letting:
[tex]\Delta s_{Fe}=27.3\frac{J}{mol*K}\\\\ \Delta s_{Fe_2O_3}=84.4\frac{J}{mol*K}\\\\\Delta s_{Al}=28.3\frac{J}{mol*K}\\\\\Delta s_{Al_2O_3}=51.00\frac{J}{mol*K}[/tex]
We obtain the entropy change per mole of Fe2O3(s):[tex]\Delta s=2*27.3\frac{J}{mol*K}+84.4\frac{J}{mol*K}-2*28.3\frac{J}{mol*K}-51.0\frac{J}{mol*K} \\\\\Delta s=31.4\frac{J}{mol*K}[/tex]
Finally, the total entropy change when 1.73 moles of Fe2O3(s) react turns out:
[tex]\Delta s=31.4\frac{J}{mol*K}*1.73mol\\\\\Delta S=54.3\frac{J}{K}[/tex]
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Why do leavening gases expand faster at higher altitudes
Answer:
Cakes, breads and other foods that contain leavening agents rise more quickly at higher altitudes, because gases produced by the agents expand faster than at sea level. The loaves may collapse if the gases dissipate before the proper temperature is reached. Most baking recipes can be adjusted for high altitudes.
Explanation:
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Write an equation that shows the formation of a cesium ion from a neutral cesium atom.
Answer:
Cesium is an Element in the Periodic table with atomic number 55, symbol Cs and belongs to the first group of the metals which is Alkali metals.
Ionization energy (IE) is defined as the amount of energy consumed by a ground state gaseous atom to discharge an electron which will results in a formation of a Cation
It forms ions be releasing the electron
[tex]Cs(g) + IE[/tex] → [tex]Cs^+ + e^-[/tex] IE= 38.939 KJ
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Which element has the same number of electrons in the outermost energy level at Lithium?
A. Hydrogen
B. Beryllium
C. Carbon
D. Magnesium
Answer:
Hydrogen is your answer because lithium and hydrogen both have 1 electron in their outermost energy level
H E L P I NEED HELPPP!!!! The primary purpose of the experimental method is to *
solve problems.
design experiments.
make observations.
publish theories.
Answer:
The answer is make observations
Explanation:
Observing is the first step of the experimental method.
What happens to sugar in a cup of tea?
After burning your candle for a few hours you and your friend notice that it's mass has decreased. Your friend claims that the mass "disappeared". Why do you know he is wrong (Hint: it's a Scientific Law)? What actually happened to the mass? What form is that mass in now? What is this process called?
Answer:
The law of conversion of mass is a scientific law that says that mass or matter can not be created or destroyed like energy but changes its form in a different type of state. So, by the law of conversion of mass, you can say that mass is not disappeared but change in different forms of states of matter like gas, soot, or melted residues of candle and ash of thread.
Due to this, the mass of the solid or waxy state due to burning changes to gas released by burning and residue of wax that will be equal to the mass of the original mass.
List 2 differences between an ionic and covalent chemical bond
According to the ,cell theory where do cells come from?
Answer:
cells come from pre existing cells
Convert 1.5x10^25 atoms of hydrogen into moles of Hydrogen
Genchemium, a hypothetical metal with a atomic mass of 150 g/mol, has a body-centered (bcc) cubic unit cell and a density of 1.93 g/cm3. What is the edge length (in pm) of genchemium
Answer:
edge length a = 636.7 pm
Explanation:
If you check the image below, you would see that there is a technical error that makes it unable to submit the answer, but to curb that effect, I have attached the screenshot of my answer showing how explained it by using the text-editor.
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The edge length (in pm) of the hypothetical metal genchemium is;
a = 0.6367 pm
We are given;
Atomic mass; M = 150 g/mol
Density; ρ = 1.96 g/cm³
This is a BCC structure and as such formula to find the edge length is;
ρ = (z × M)/(N × a³)
where;
z = number of atoms available in each unit cell = 2 atoms
M is atomic mass
N is avogadro's number = 6.023 × 10²³ mols
a is edge length
Thus, making a the subject gives;
a = ∛(z × M)/(N × ρ)
Plugging in the relevant values;
a = ∛(2 × 150)/(6.023 × 10²³ × 1.96)
a = 63.67 × 10⁻⁹ cm
converting to meters gives;
a = 0.6367 × 10⁻⁹ m
converting to pm gives;
a = 0.6367 pm
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Rhodium crystallizes in a face-centered cubic unit cell. The radius of a rhodium atom is 135 pm. Determine the density of rhodium in g/cm3
Answer:
Density of unit cell ( rhodium) = 12.279 g/cm³
Explanation:
Given that:
The radius (r) of a rhodium atom = 135 pm
The atomic mass of rhodium = 102.90 amu
For a face-centered cubic unit cell,
[tex]r = \dfrac{a}{2\sqrt{2}}[/tex]
where;
a = edge length.
Making "a" the subject of the formula:
[tex]a = 2 \sqrt{2} \times r[/tex]
[tex]a = 2 \times 1.414 \times 135 \ pm[/tex]
a = 381.8 pm
to cm, we get:
a = 381.8 × 10⁻¹⁰ cm
However, recall that:
[tex]density \ of \ unit \ cell = \dfrac{mass \ of \ unit \ cell}{volume \ of \unit \ cell}[/tex]
where;
mass of unit cell = mass of atom × numbers of atoms per unit cell
Also;
[tex]mass\ of\ atom =\dfrac{ atomic \ mass}{Avogadro \ number}[/tex]
[tex]mass\ of\ atom =\dfrac{ 102.9}{6.023 \times 10^{23}}[/tex]
Recall also that number of atoms in a unit cell for a face-centered cubic = 4
So;
[tex]mass \ of \ unit \ cell= \dfrac{102.90}{6.023 \times 10^{23}}\times 4[/tex]
mass of unit cell = 6.83380375 × 10⁻²² g
[tex]Density \ of \ unit \ cell = \dfrac{6.83380375 \times 10^{-22}}{(381.8\times 10^{-10})^3}[/tex]
Density of unit cell ( rhodium) = 12.279 g/cm³
The density of rhodium is equal to 12.4g/cm^3
Data;
radius = 135pmatomic mass = 102.90 amuThe radius of a FCC is calculated as
[tex]r = \frac{a}{2\sqrt{2} }\\a = 2\sqrt{2} * r\\a = 2 * 1.414 * 135 = 381.8pm = 381.8 * 10^-^1^0cm\\[/tex]
The Density of RhodiumThe formula of density is given as
[tex]\rho = \frac{mass}{volume}\\[/tex]
The mass of a unit cell = mass of atom * number of atoms per unit cell.
[tex]mass of atom = \frac{atomic mass}{avogadro's number} = \frac{102.90}{6.023*10^2^3}\\[/tex]
For BCC number of atom in unit cell = 4
mass of unit cell = [tex]\frac{102.90}{6.02*10^2^3} * 4[/tex]
This makes the density of the atom equal to
[tex]\rho = \frac{\frac{102.90}{6.02*10^2^3} }{(381*10^-^1^0)^3}* 4\\ \rho = 12.4 g/cm^3[/tex]
The density of Rhodium is 12.4 g/cm^3
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Answer:
the answer is b I am sure
A sample of an unknown metal has a mass of 22.4g. A graduated cylinder contains 3.2 ml of water. After the metal sample is added to the graduated cylinder, the water level reads 4.7 ml. Calculate the density of the metal
Answer:
d = 14.9 g/mL
Explanation:
Given data:
Mass of metal = 22.4 g
Volume of eater = 3.2 mL
Volume of water + metal = 4.7 mL
Density of metal = ?
Solution:
Volume of metal:
Volume of metal = volume of water+ metal - volume of water
Volume of metal = 4.7 mL - 3.2 mL
Volume of metal = 1.5 mL
Density of metal:
d = m/v
d = density
m = mass
v = volume
d = 22.4 g/ 1.5 mL
d = 14.9 g/mL
why are elements in the column with helium so stable ?
Answer:
Explanation:
because they have complete valence shell thats why they are not reactive towards chemical reaction and are quite stable
4. A 40.0L tank of ammonia has a pressure of 12.7 kPa. Calculate the volume of the
ammonia if its pressure is changed to 8.4 kPa while its temperature remains constant.
Answer:
V₂ = 60.47L
Explanation:
Given data:
Initial volume = 40.0 L
Initial pressure = 12.7 KPa
Final volume = ?
Final pressure = 8.4 KPa
Solution:
The given problem will be solved through the Boyls law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
12.7 KPa× 40.0 L = 8.4 KPa × V₂
V₂ = 12.7 KPa× 40.0 L/ 8.4 KPa
V₂ = 508 KPa. L / 8.4 KPa
V₂ = 60.47L
The volume of the ammonia gas if it's pressure is changed to 8.4 KPa is 60.5 L
From the question given above, The following data were obtained:
Initial pressure (P₁) = 12.7 KPa
Initial volume (V₁) = 40 L
Final pressure (P₂) = 8.4 KPa
Temperature = constant
Final volume (V₂) = ?Using the Boyle's law equation, the final volume of the ammonia can be obtained as illustrated below:
P₁V₁ = P₂V₂
12.7 × 40 = 8.4 × V₂
508 = 8.4 × V₂
Divide both side by 8.4
V₂ = 508 / 8.4
V₂ = 60.5 LTherefore, the final volume of the ammonia gas is 60.5 L
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What class of organic product results when 1-heptyne is reacted with disiamylborane followed by treatment with basic hydrogen peroxide?
Answer:
aldehyde
Explanation:
Aldehydes are a large class of reactive organic compounds (R-CHO) having a carbonyl functional group attached to one hydrocarbon radical and a hydrogen atom.
So, when terminal alkynes, for example, 1-heptyne react on Hydroboration oxidation(i.e. disiamylborane followed by treatment with basic hydrogen peroxide), the formation of aldehyde occurs.
