[tex] \qquad \huge \underline{ \boxed{\sf Answer}}[/tex]
Here's the correct choices for the blank questions~
# 1 : position - time graph
#2 : Displacement - time graph
#3 : Motion graphs
#4 : Ticker tape diagram
#5 : Wave
#6 : Amplitude
#7 : Frequency
The answers to the questions are as follows :
Position time graphs ( E ) Displacement time graph ( B )Motion graphs ( D )Ticker tape diagram ( F ) Wave ( G ) Amplitude ( A ) Frequency ( C ) The different types of motion graphsPosition time graphs are motion graphs that show the change in an object position in relation to time traveled, while a displacement time graph shows if an object is going backwards or forward and unlike distance, she does not consider the direction of movement of an object.
Motion graphs are used for the presentation of the motion of objects visually.
Hence we can conclude that the answers to your questions are as listed above.
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Question #1
Given the free body diagram below, which direction will the object accelerate? Assume that the length of
Fair is the same as Fapp.
Given the diagram provided, we can confirm that the object will accelerate in a downward direction.
Why will it accelerate downwards?The free-body diagram shows us the forces that are acting on this object. Through this diagram, we can see that the forces on the left and right of the object are balanced, meaning that there will not have movement in either of these directions.
The diagram shows that the downward force being applied is not balanced by an opposite force, so the object will accelerate in this direction.
Therefore, we can confirm that object will accelerate in a downward direction due to its downward force not being balanced by an opposing force.
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A 2-kg block is thrown upward from a point 20 m above the Earth's surface. At what height above Earth's surface will the gravitational potential energy of the Earth-block system have increased by 500 J?
Answer:
45.5 m
Explanation:
m = 2 kg, h = 20 m, E = 500 J, radius of earth = R, mass of earth = M
find the new height H
at h, the potential energy = -GMm/(R + h)
at H, the potential energy = -GMm/(R + H)
increase of the potential energy
= [-GMm/(R + H)] - [-GMm(R + h)]
= GMm[1/(R + h) - 1/(R + H)] = E
1/(R + h) - 1/(R + H) = E/(GMm)
(H - h)/[(R + H)(R + h)] = E/(GMm)
R + h ≈ R, R + H ≈ R
so (H - h)/R² = E/(GMm)
H - h = ER²/(GMm)
note GM/R² = g = 9.81 m/s²
so H - h = E/(mg)
H = h + E/(mg) = 20 + 500/(2*9.81) = 45.5 m
Which car is faster A or B
Answer:
A
Explanation: Car A is the fastest
Calculate how long it takes Neptune in earth years for one trip around the sun by using an average Sun-Neptune distance of 30 A.U. ( ) 0.735 earth years Show calculation: ( ) 1.84 earth years ( ) 3.37 earth years ( ) 164 earth years
Answer:
164 earth years
Explanation:
By Kepler's third law
r³/T² = constant
(30 A.U)³/T² = (1 A.U.)³/(1 earth year)²
so T = 30^1.5 = 164 earth years
Help me pls, I need it now
6.) a
7.) d
8.) b
9.) b
10.) a
1. a
2. d
3. b
4. b
5. a
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What is the average power consumption in watts of an appliance that uses 5.00 KW.h of energy per day?
what negative influences must be avoided to be able to achieve your goal mention at least 3
The negative influences that must be avoided in order to achieve your goal are excuses, procrastination and distractions.
What is negative influence?A negative influence is someone or something that induces negative or bad action in someone. This bad influence can create bad energy within and corrupt good mind.
Three negative influence to avoidAvoid excusesAvoid procrastinationAvoid distractions.Thus, the negative influences that must be avoided in order to achieve your goal are excuses, procrastination and distractions.
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The speed of sound is measured to be 336 m/s on a certain day. What is this measurement in kilometers per hour
Answer:here’s how you do it
Explanation:
A student shines a mixture of red and blue light onto a blue toy car what color will the car appear to have explain your answer
Answer:
If we use a mixture of red and blue light, the blue toy car might reflect deep magenta color. If the toy car is made up of metal, it might reflect glittery magenta color. If the intensity of the blue color is greater, the toy car might show dark blue color
Explanation:
is this right please let me know:D
Rick's car has a mass of 1000 kg and its brakes can apply 8000 N of force. If he is driving at 32 m/s and sees something in the road suddenly, how long will it take his car to come to a stop? Use the equation below to help you.
Answer:
Given:
m=1000kg
F=8000 N
u=32m/s
v=0m/s
Required:
T=?
Solution:
F=m × a
8000N = 1000kg × a
a = 8m/s^2
Since it's deceleration -8m/s^2
a= v - u / t
-8m/s^2 = 0 - 32m/s / T
T = 4 s
Hence the car takes 4sec to stop
Please follow me
The stopping time of the car is equal to 4 seconds.
What is speed?Speed is defined as the ratio of the time distance travelled by the body to the time taken by the body to cover the distance. Speed is the ratio of the distance travelled by time. The unit of speed in miles per hour.
Given that,
m=1000kg
F=8000 N
u=32m/s
v=0m/s
The acceleration will be calculated by the formula below,
F = m × a
8000N = 1000kg × a
a = 8 m/s²
Since its deceleration -8m/s². The time taken is calculated by the formula,
a= v - u / t
-8= (0 - 32 ) / t
t = 32 / 8
t = 4 seconds
Therefore, the stopping time of the car is equal to 4 seconds.
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A 2kg rock is at the edge of a cliff 20m above the surface of a lake. It comes loose and falls. Half way down it is falling at 14 m/s. What is its Kinetic Energy at the half way point?
Please show work!
Answer:
196 Joules
Explanation:
kinetic energy = 1/2 * mass * velocity²
Given:
mass: 2 kgvelocity: 14 m/susing formulae:
[tex]\rightarrow \sf kinetic \ energy = \dfrac{1}{2} * 2 * 14^2[/tex]
[tex]\rightarrow \sf kinetic \ energy = 196 \ J[/tex]
(06.02 MC)
What can a scientist use to observe very small things?
Answer:
microscopic light or Nano technology
Okay the question is calculate the current when 1200C of charge flows through a wire in 200 s.
Hi there!
Using the equation for current:
[tex]I = \frac{\Delta Q}{\Delta t}[/tex]
I = Current (A)
Q = Charge (C)
t = time (s)
Therefore, the current is equivalent to the amount of charge passing through a wire over a given time interval.
We can plug in the given values and solve.
[tex]I = \frac{1200}{200} = \boxed{6 A}[/tex]
