May I ask a question?if I have a 10 girls in a class and the total number of students in the class are 30, what's the percentage of the total amount of girls?

Answers

Answer 1

Given:

The number of girls =10 and the total number of students =30.

The percentage of the total amount of girls is

[tex]=\frac{The\text{ number of girls}}{\text{The total number of students}}\times100[/tex]

[tex]=\frac{10}{30}\times100[/tex]

[tex]=33.33[/tex]

Hence the percentage of the total amount of girls is 33.33 %.


Related Questions

Suppose that an item regularly costs $100.00 and is discounted 22%. If it is then marked up 22%, is the resulting price $100.00? If not, what is it? Choose the correct answer below and, if necessary, fill in the answer box to complete your choice.

Answers

Suppose that an item regularly costs $100.00 and is discounted 22%. If it is then marked up 22%, is the resulting price $100.00? If not, what is it? Choose the correct answer below and, if necessary, fill in the answer box to complete your choice.​

1)

we have

100%-22%=78%=78/100=0.78

so

If is discounted 22%

the new price is 100,000*0.78=$78,000

2) If it is then marked up 22%

the new price is

100%+22%=122%=122/100=1.22

78,000*1.22=$95,160

therefore

The new price is not $100,000

the new price is $95,160

LM is the midsegment of Trapeziod RSXY. may you please help me find what LM is?

Answers

Step 1: Problem

Mid-point of a Trapezoid

Step 2: Concept

[tex]LM\text{ = }\frac{RS+\text{ YX}}{2}[/tex]

Step 3: Method

RS = 4.1

YX = 8.2

[tex]\begin{gathered} LM\text{ = }\frac{4.1\text{ + 8.2}}{2} \\ LM\text{ = }\frac{12.3}{2} \\ LM\text{ = 6.15} \end{gathered}[/tex]

Step 4: Final answer

LM = 6.15

Megan's text messaging plan cost $15 for the first 600 messages and 5¢ for each additional text message. If she owes $24.60 for text messaging in the month of October, how many text messages did she send that month

Answers

Megan sent  792 text messages in the month of October .

In the question ,

it is given that

Cost for first 600 messages = $15

additional text message charge = $0.05

Amount owed by Megan for the month of October = $24.60

Let the number of Additional messages be x.

So, according to the question

15 + 0.05x = 24.60

0.05x = 24.60-15

0.05x = 9.6

x = 9.6/0.05

x = 192

number of extra messages = 192

total messages = first 600 messages + extra messages

= 600+192

= 792

Therefore , Megan sent 792 text messages in the month of October .

The given question is incomplete , the complete question is

Megan's text messaging plan cost $15 for the first 600 messages and 5¢ for each additional text message. If she owes $24.60 for text messaging in the month of October, how many text messages did she send that month ?

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How do you write 6 tens + 4 ones + 5 tenths + 2 hundredths + 8 thousandths

Answers

Answer:

Step-by-step explanation:

64.528 is the decimal

64.528 would be the numerical form of the alphabetical order you listed your question in

Seventeen percent of people say they've seen a ghost or felt its presence. If 10 people are asked, what is the probability that at least two have seen a ghost or felt its presence?Round your answer to at least three decimals.

Answers

Answer: the probability that at least two have seen a ghost or felt its presence is 0.527

Explanation:

In this scenario, it is either a person asked has seen seen a ghost or felt its presence or they have not. These outcomes are independent of each other. Thus, it's a binomial distribution. We would apply the formula for calculating binomial probability which is expressed as

P(x) = nCx * p^x * q^(n - x)

where

p = probability of success

q = 1 - p = probability of failure

n = sample size

x = number of successes

From the information given, we are concerned with the people that say they've seen a ghost or felt its presence. Thus,

p = 17% = 17/100 = 0.17

q = 1 - 0.17 = 0.83

n = 10

x = 2

We want to find P(x ≥ 2)

P(x ≥ 2) = 1 - [P(x = 0) + P(x = 1)

P(x = 0) = 10C0 * 0,17^0 * 0.83^(10 - 0) = 0.1552

P(x = 1) = 10C1 * 0,17^1 * 0.83^(10 - 1) = 0.3178

P(x ≥ 2) = 1 - (0.1552 + 0.3178) = 1 - 0.473

P(x ≥ 2) = 0.527

the probability that at least two have seen a ghost or felt its presence is 0.527

Tye mapping diagram below matches the points on the graph next to it.find the value of X

Answers

Given,

The coordinates of the points shown in the graph is:

[tex](-6,2),\text{ \lparen6,2\rparen, \lparen6,1\rparen and \lparen3,1\rparen}[/tex]

Here, the given mapping is:

[tex](-6,2),\text{ \lparen6,2\rparen, \lparen x,1\rparen and \lparen3,1\rparen}[/tex]

On comparing the coordinates then x = 6.

Hence, the value of x is 6.

a.a + 0 = 0Additive Identityb. Multiplicative IdentityCommutative Property of Additiond. Associative Property of AdditionC.

Answers

Answer:

a. Additive Identity

Explanation:

Given the equation:

[tex]a+0=a[/tex]

When zero(0) is added to 'a', the result is still 'a'.

The number 0 is the additive identity of 'a'.

May I please get help with this. For I have tried multiple times but still can’t get the right answer or the triangle after dilation?

Answers

Solution:

Given the triangle ABC as shown below:

To draw the image,

step 1: Determine the coordinates of the vertices of the triangle.

In the above graph,

[tex]\begin{gathered} A(6,7) \\ B(9,9) \\ C(8,6) \end{gathered}[/tex]

step 2: Evaluate the new coordinates A'B'C' of the triangle after a dilation centered at the origin with a scale factor of 2.

After a dilation centered at the origin with a scale factor of 2, the iniatial coordinates of the vertices of the triangle are multiplid by 2.

Thus,

[tex]\begin{gathered} A(6,7)\to A^{\prime}(12,14) \\ B(9,9)\to B^{\prime}(18,18) \\ C(8,6)\to C^{\prime}(16,12) \end{gathered}[/tex]

step 3: Draw the triangle A'B'C'.

The image of the triangle A'B'C' is as shown below:

This is a graph of the motion of a small boat traveling at a constant speed. Total Distance Traveled 12 10 8 Distance (Kilometers) 6 0 2 4 6 8 1012 Time (Hours) How far will the boat travel in 15 hours? O A. 25 km O B. 30 km O C. 15 km O D. 10 km

Answers

The speed of the boat is given by the gradient of the line.

Given two points (x1,y1) and (x2,y2) on a graph, the gradient of the line that passes through the two points is given by

[tex]\text{ gradient = }\frac{y_2-y_1}{x_2-x_1}[/tex]

In this case,

the line passes through the points (0,0) and (2,2).

We can set (x1,x2) = (0,0) and (y1,y2) = (2,2)

Therefore,

[tex]\begin{gathered} \text{ gradient = }\frac{2-0}{2-0}=\frac{2}{2}=1 \\ \text{therefore} \\ \text{the speed = 1km/h} \end{gathered}[/tex]

Given that a body travels with speed, s, and in time, t, the distance travelled, d, is given by

[tex]d=st[/tex]

In this case,

s = 1km/h, and t = 15hours

Therefore,

[tex]d=1\times15=15\operatorname{km}[/tex]

Therefore, the boat travelled a distance of 15km

Solve the problems below as fast as you can because I’m trying to go to sleep but it’s not an assignment or graded or timed please

Answers

Given the inequality:

4m < 24

Let's solve for m.

To solve for m, divide both sides of the inequality by 4:

[tex]\begin{gathered} \frac{4m}{4}<\frac{24}{4} \\ \\ m<6 \end{gathered}[/tex]

ANSWER:

m < 6

Which expression is equivalent to -(-r - 16)?

Answers

Answer: Hi that would be (r+16) since they are generally the same thing, hope this is what you are asking for!

Step-by-step explanation:

find the value of XA. 11√ 41inB. 11 inC. 33 inD. 35 in

Answers

From the diagram provided, we have a right angled triangle with the hypotenuse (side facing the right angle) given as 55, while one of the other two sides is given as 44.

We shall apply the pythagoras' theorem as follows;

[tex]c^2=a^2+b^2[/tex]

Where,

c = hypotenuse,

a and b = the other sides.

Therefore, we'll now have;

[tex]\begin{gathered} c^2=a^2+b^2 \\ 55^2=44^2+c^2 \\ 3025=1936+c^2 \end{gathered}[/tex]

Next step, we'll subtract 1936 from both sides of the equation;

[tex]\begin{gathered} 3025-1936=1936-1936+c^2 \\ 1089=c^2 \end{gathered}[/tex]

Add the square root sign to both sides of the equation;

[tex]\begin{gathered} \sqrt[]{1089}=\sqrt[]{c^2} \\ 33=c \end{gathered}[/tex]

ANSWER

Therefore, the correct answer is option C, that is 33 inches.

Given f(x)=6(1-x), what is the value of:a) f(-8)_____b) f(x) = -30 _____c) f(x) = 30____d) f(30)_____

Answers

Answer:

a) f(-8) = 54



b) f(x) = -30, x = 6



c) f(x) = 30, x = -4



d) f(30) = -174

Explanation:

Given the function:

f(x) = 6(1 - x)

To find f(-8), we replace x by -8 in the equation and then solve

f(-8) = 6[1 - (-8)8]

= 6(1 + 8)

= 6(9)

= 54

For f(x) = -30, we replace f(x) by -30 and solve for x

-30 = 6(1 - x)

Divide both sides by 6

1 - x = -30/6 = -5

Subtract 1 from both sides

-x = -6

Multiply both sides by -1

x = 6

For f(x) = 30, we replace f(x) by 30 and solve for x

30 = 6(1 - x)

Divide both sides by 6

1 - x = 30/6 = 5

Subtract 1 from both sides

-x = 4

Multiply both sides by -1

x = -4

f(30) = 6(1 - 30)

= 6(-29)

= -174

4)Describe the difference between a sampling error and non-sampling error .

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

sampling error and non-sampling error

Step 02:

statistics:

Sampling error:

It is the error that arises in a data collection process as a result of taking a sample from a population rather than using the whole population.

Non-sampling error:

It is the error that arises in a data collection process as a result of factors other than taking a sample.

non-response errors, coverage errors, interview errors, and processing errors

Find the area of the figure.A. 57 square yardsB. 66 square yardsC. 180 square yards D. 234 square yards

Answers

We would section the figure into two shapes as shown below

We can see a trapezium and a rectangle. We would find the area of each figure and add them.

For the trapezium,

Area = 1/2 * (a + b)h

a nd b are the opposite sides of the trapezium while h represents the height.

Thus,

a = 20, b = 24 and h = 9es of the trapezium while h represents the height.

Thu sid

Write an equation for the line through the point (x0,y0) with a slope of M in point slope form. Enter X0 and Y0 as y0. Use X and Y for variables names. Your equation should be of the form y=….

Answers

The equation of the line in point slope form is  y = M(x - x₀) + y₀ .

The Point slope form of the line passing through the point (x₁,y₁) with slope m is given by the formula

(y - y₁) = m(x - x₁)

In the question ,

it is given that

the required line passes through the points (x₀ , y₀)

and the slope is M .

So, the point slope form equation of the line will be

( y - y₀) = M(x - x₀)

y - y₀ = M(x - x₀)

y = M(x - x₀) + y₀

Therefore , the equation of the line in point slope form is  y = M(x - x₀) + y₀ .

The given question is incomplete , the complete question is

Write an equation for the line through the point (x₀,y₀) with a slope of M in point slope form. Your equation should be in the form of y = ...    ?

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Which of the following sampling methods would most likely have the smallest margin of erro?A. Roll a die 1000 times and estimate the proportion of 5's that result.OB. Sample 250 registered voters in a large city and ask them their political preference and use the results to estOC. Flip a coin 100 times and estimate the proportion of "heads" that resul.OD. Sample 10 adults and ask them if they support the current President's foreign policy and use this data to reReset SelectionMext

Answers

The sample methodology whose accuracy is better than another is the one with more approximation, this comes from the number of repetitions.

Therefore, option A is the one with more approximation, which mean the least error margin.

Tara makes and sells scarves for children and adults. She is able to sell the scarves for $18 per unit. Materials for the scarves cost $4 each. She has fixed cost per month of $280 and estimates that she can make and sell 80 scarves each month. How many scarves does Tara need to sell to break even?

Answers

Tara needs to sell 20 scarves to break even.

What is the break-even point?

The break-even point is the sales level that the seller must attain to make the total revenue equal to the total costs (fixed and variable).

There is no profit or loss at the break-even point (either in units or dollar values).

Selling price per unit = $18

Product cost per unit = $4

Contribution margin per unit = $14

Fixed cost per month = $280

Estimated production and sales units per month = 80 scarves

Break-even sales units = fixed costs/contribution margin per unit

= 20 ($280/$14)

Check:

Total revenue at 20 units = $360 (20 x $18)

Total costs at 20 units = $360 ($280 + $4 x 20)

Thus, for Tara to break even, she needs to sell 20 scarves per month.

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Solve the following expression when p = 15 p/3 + 4

Answers

[tex]\frac{p}{3}+\text{ 4= }\frac{15}{3}+4\text{ = 5+4= 9}[/tex]

So, our answer is 9!

could you please help me answer this please and thank you it's about the rectangular prism....

Answers

ANSWER:

[tex]A_T=8+8+20+20+40+40[/tex]

STEP-BY-STEP EXPLANATION:

In this case, what we must do is calculate the face area and then add each face, like this:

The area of each area is the product between its length and its width, therefore

[tex]\begin{gathered} A_1=2\cdot4=8 \\ A_2=10\cdot4=40 \\ A_3=10\cdot2=20_{} \\ A_4=10\cdot4=40 \\ A_5=10\cdot2=20_{} \\ A_6=2\cdot4=8 \end{gathered}[/tex]

The total area would be the sum of all the areas, if we organize it would be like this:

[tex]A_T=8+8+20+20+40+40[/tex]

Find the solutions to the following quadratic equation negative 3X squared plus 4X plus one equals zero (-3x^2 + 4x + 1 = 0)

Answers

Answer:

Explanation:

Given:

[tex]-3x^2+4x+1=0[/tex]

To find:

the value of x using the quadratic formula

The quadratic formula is given as:

[tex]$$x\text{ = }\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$$[/tex]

where a = -3, b = 4, c = 1

[tex]\begin{gathered} x\text{ = }\frac{-4\pm\sqrt{(4)^2-4(-3)(1)}}{2(-3)} \\ \\ x\text{ = }\frac{-4\pm\sqrt{16+12}}{-6} \\ \\ x\text{ = }\frac{-4\pm\sqrt{28}}{-6} \end{gathered}[/tex][tex]undefined[/tex]

write a part to part and a part to whole ratio for each problem situationof the 250 students surveyed 142, prefer carrots and 97 prefer peas

Answers

Here, we want to write ratios in part to part and in part to whole ratio

For the part to part

Writing carrot to peas, we have;

[tex]142\colon97[/tex]

For the parts to whole ratio, we have;

[tex]\begin{gathered} \text{Carrot} \\ \frac{142}{250}\text{ = 142:250} \\ \text{Peas} \\ \frac{97}{250}\text{ = 97:250} \end{gathered}[/tex]

why is height more specific measure than 'size'?

Answers

When you talk about height, it is a more precise value that require a vertical distance from a referenced point. While 'size' is not specific whatsoever and it's more like a form of range.

Find the lateral surface area and volume of the object in picture below

Answers

So first of all we have to find the lateral surface of the truncated pyramid. This surface is composed of 4 equal trapezoids. The are of a trapezoid is given by half the sum of its bases multiplied by its height. The large base of these faces are 6' long, the short base are 5' long and their height are 2.1' long. Then the area of each trapezoid is:

[tex]\frac{(6^{\prime}+5^{\prime})}{2}\cdot2.1^{\prime}=11.55in^2[/tex]

Then the total lateral surface is:

[tex]11.55in^2\cdot4=46.2in^2[/tex]

Then we need to find the volume of the truncated pyramid. This is given by the following formula:

[tex]\frac{1}{3}h(a^2+ab+b^2)[/tex]

Where a and b are the bottom and top side of its two square faces and h is the height of the pyramid i.e. the vertical distance between bases. The lengths of the bases is 5' and 6' whereas the height of the pyramid is 2' then its volume is given by:

[tex]\frac{1}{3}\cdot2^{\prime}\cdot(5^{\prime2}+6^{\prime}\cdot5^{\prime}+6^{\prime2})=60.7in^3[/tex]

In summary, the lateral surface is 46.2in² and the volume is 60.7in³.

Find an equation of line L. Write your answer using fractions or integers.The equation of line L is y =

Answers

Find slope m, in equation y= mx + b

m = Y/X =( y - y')/ (x - x')

m= (5 - -5 )/ (-3 -3) = 10/-6 = -5/3

Now find b

b = y - mx

= 5 - (-5/3)•-3

. = 5 - 5 = 0

b = 0

Then answer is, equation is

y = (-5/3)x

does (51, 58) make the equation y =x -7 true?

Answers

The objective is to verify whether the point (51,58) maes the equation y=x-7.

Substitute the values of x and y coordinate in the given equation.

[tex]\begin{gathered} y=x-7 \\ y-x=-7 \\ 58-51=-7 \\ 7=-7 \end{gathered}[/tex]

Since, LHS is not equal to RHS.

Thus, the coordinate (51,58) does not make the equation y=x-7.

Hence the answer is NO.

Which inequalities are shown on the graph?Find your inequalities in the grid below. Check the ONE box that pairs the two correct inequalitiesY-3-1 y>-**-172-**-1 y<-**-1<3+3y>+3y< <+3y2 ++3D D D DOOOO"OOOOPreviousPauseO Search for anything0-

Answers

From the graph we could see that y = x + 3 for the first line . The shaded line is where y is less than or equals to x + 3.

For the second line we can see that y = x - 1 . The shaded line is where y is greater than or equals to x - 1 . Therefore, the inequalities are as follows

[tex]\begin{gathered} y\leq x+3 \\ y\ge x-1 \end{gathered}[/tex]

......................

Answers

Answer: x 0 1 2 3

p(x) 0.011 0.170 0.279 0.539

Given that the values of x =

Television 0 1 2 3

Household 30 443 727 1401

Let television be = x

Household = frequency = distribution

Firstly, we need to find the interval of x

The interval of x = Range between two numbers

1 - 0 = 1

2 -1 = 1

3 - 2 = 1

Hence, the interval is 1

[tex]p(x)\text{ = }\frac{frequency\text{ for x interval}}{N\text{ x w}}[/tex]

Where N = total frequency

w = interval

Total frequency = 30 + 443 + 727 + 1401

Total frequency = 2601

[tex]\begin{gathered} \text{when x = 0} \\ p(x)\text{ = }\frac{30}{2601\text{ x 1}} \\ p(x)\text{ = }\frac{30}{2601} \\ p(x)\text{ = }0.011 \end{gathered}[/tex]

when x = 1

[tex]\begin{gathered} p(x)\text{ = }\frac{443}{2601\text{ x 1}} \\ p(x)\text{ = }\frac{443}{2601} \\ p(x)\text{ = 0}.170 \end{gathered}[/tex]

When x = 2

[tex]\begin{gathered} p(x)\text{ = }\frac{727}{2601\text{ x 1}} \\ p(x)\text{ = }\frac{727}{2601} \\ p(x)\text{ = 0.279} \end{gathered}[/tex]

when x = 3

[tex]\begin{gathered} p(x)\text{ = }\frac{1401}{1\text{ x 2601}} \\ p(x)\text{ = }\frac{1401}{2601} \\ p(x)\text{ = 0.539} \end{gathered}[/tex]

Therefore,

x 0 1 2 3

p(x) 0.011 0.170 0.279 0.539

Find the x-intercept and y-intercept of the line.
5x-9y=-12

Answers

The x and y intercepts of the line is found as (12/5, 0) and (0, -4/3) respectively.

What is termed as the x and y intercepts?An intercept is a y-axis point that the slope of a line passes. It is the y-coordinate of the a point on the y-axis where a straight line or even a curve intersects. This is represented by the equation for a straight line, y = mx+c, where m is the slope and c seems to be the y-intercept. There are two types of intercepts: x-intercept and y-intercept.

For the given question,

The equation of the line is 5x-9y=-12.

For the x intercept, Put y = 0.

5x-9×0=-12.

x = 12/5

x intercept = (12/5, 0)

For y intercept, put x = 0.

5×0-9y=-12

y = -12/9

y = -4/3

y intercept = (0, -4/3)

Thus, the x and y intercepts of the line is found as (12/5, 0) and (0, -4/3) respectively.

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X + 2y = 3x = 5Enter your answer as a point using parenthesis and a comma. Do not use any spaces in youranswer.If there are no solutions, type "no solutions." If there are infinitely many solutions, type"infinitely many."Answer:

Answers

[tex]\begin{gathered} x+2y=3 \\ 5+2y=3 \\ 5+2y-5=3-5 \\ 2y=-2 \\ \frac{2y}{2}=-\frac{2}{2} \\ y=-1 \end{gathered}[/tex]

thats the explanation

answer is : (5, -1)

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