Slope And Rate Of Change

Prior to 1982, pennies weighed 3.1 grams. Coins produced after 1982 weigh 2.5 grams. 647 coins from each period are there in the bag if it contains 1267 pennies and weighs 3541.9 grams.

Given that,

The 1982 change in pennies composition from all copper to zinc with copper coating was made by the US Mint. Prior to 1982, pennies weighed 3.1 grams. Coins produced after 1982 weigh 2.5 grams.

We have to find how many coins from each period are there in the bag if it contains 1267 pennies and weighs 3541.9 grams.

An issue of quantity and amount. In this context, the term "amount" refers to weight. The variables should be identified with letters that will make them easy to distinguish: Z for largely zinc and C for all copper. Create weight and quantity equations:

C + Z = 1287

3.1 C + 2.5 Z = 3601.5

By multiplying all three components of the first equation by -2.5 and placing them under the second equation, drawing a line, and then subtracting, you can eliminate the Z using this method.

3.1 C + 2.5 Z =  3601.5

-2.5 C -  2.5 Z = -3217.5

--------------------------------

0.6 C              =    384      

Divide both sides by .6.

C = 640        

Subtract 640 from 1287.

Z = 647

Therefore, 647 coins from each period are there in the bag if it contains 1267 pennies and weighs 3541.9 grams.

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The equation models this scenario regarding the hiker is x - 450 = 2300.

Elevation is simply used to illustrate the height above the sea level.

In this case, the hiker descended 450 feet down to an elevation of 2300 feet.

The equation that can model the scenario will be x - 450 = 2300

where x = Initial elevation

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Answer:

$754.92

Step-by-step explanation:

699.00 plus 8% of 699.00 is 754.92

Answer:

x=50

Step-by-step explanation:

5(2-x)-10=25-2(3x+40)

Distribute:

10-5x-10=25-6x-80

Combine like terms

-5x-10=-6x-55

Put x to one side

x-10=-55

Make x by itself

x=-55

Answer:  x=−55

Step-by-step explanation:

Solve the equation step-by-step:

5(2−x)−10=25−2(3x+40)

Simplify both sides:

5(2−x)−10=25−2(3x+40)

Distribute:

(5)(2)+(5)(−x)+−10=25+(−2)(3x)+(−2)(40)

10+−5x+−10=25+−6x+−80

Combine Like Terms:

(−5x)+(10+−10)=(−6x)+(25+−80)

−5x=−6x+−55

−5x=−6x−55

Add 6x to both sides.

−5x+6x=−6x−55+6x

x=−55

since z=6, so z+15 is equal to 21

or a+k+z=21

Answer:

6 and 16

Step-by-step explanation:

→ Find the most recurring number in sequence A

6

→ Find the most recurring number in sequence B

16

Answer:

Step-by-step explanation:

[tex]4a^{2} -25=0\\(2a-5)(2a+5)=0\\2a-5=0 \\or 2a+5=0\\\\a=\frac{5}{2} \\\\or\\\\a=-\frac{5}{2}[/tex]

IF YOU CHECK CAREFULLY YOU WILL FIND THAT THIS EQAUTION IS MADE OF DIFFERENCE OF SQUARES.

GOODLUCK!!

Answer:

(2,-3)

Step-by-step explanation:

[tex]\frac{\left(y+3\right)^2}{9}-\frac{\left(x-2\right)^2}{2}=1\\\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}=1\:\mathrm{\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}\\\frac{\left(y-\left(-3\right)\right)^2}{3^2}-\frac{\left(x-2\right)^2}{\left(\sqrt{2}\right)^2} =1\\(2,-3)[/tex]

The summation is the adding two quantities thus the reasonable estimate of the total length of the trench is 1 1/2 meters so option (C) is correct.

A summation, also abbreviated as a sum, is the outcome of adding two or more numbers or quantities.

There could be only two terms, but there could be one hundred, a thousand, or a million.

Here are always an integer number of terms in a summation.

As per the given,

Length of the trench on the first day = 18/20 meters

Length of the trench on the second day = 9/20

Total length of the trench = 18/20 + 9/20

Take LCM as 20

⇒ (18 + 9)/20 = 27/20

⇒ 1.35 which is closest among the given option by 1 1/2 meters.

Hence "The summation is the adding two quantities thus the reasonable estimate of the total length of the trench is 1 1/2 meters".

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Notice that in the given sequence the difference between the first two terms is 7 so the solution must be in terms of multiples of 7 plus a constant. The only two options that have this characteristic are first and last ones, for the sum to consider the first term the sum must start for r=0.

Answer: last option.

Answer:

(1,3)

Step-by-step explanation:

You can use the distance formula to help you solve the answer

Answer:

(1; 3)

Step-by-step explanation:

x = (-1 + 3)/2 = 1

y = (6 + 0)/2 = 3

The given expression is

First, we change 1/3 for its reciprocal to transform the division into a product.

Then, we multiply the fractions.

At last, we transform the fraction into a mixed fraction.

Answer:

17. s = 9

18. x = 8x^(½)

Step-by-step explanation:

s² - 7 = 74?

s² = 74 + 7

s² = 81

√(s²) = √(81)

s = 9

x² - 8x = 0

x² = 0 + 8x

x² = 8x

√(x²) = √(8x)

x = 8x^(½)

OR by factoring

x²−8x=0

x(x−8)=0

x=0 or x−8=0

x=0 or x=8

The probability of no loads occurring during that period is at most 0.3 exists 3.2 years.

Given: Mean time between occurrence = 0.4 year

A number of loads expected to occur during a 4 year period

Period = 4

Mean time = 0.4

Let the formula = Period/Mean Time

The number of loads expected to occur during a 4-year period

= 4/0.4 = 10 loads

B. Probability that more than 11 loads occur during 4 year period

The expected number of loads during 4-year period = 10 (from A above)

mean = 10

Using Poisson distribution,

P(k events in interval)= (λ^k * e^-k)/k!

where: k = 0, 1, 2,3,4, . . ., 11 and λ = 10.

P(k = 0) = (1[tex]0^0[/tex] × [tex]e^{-10[/tex])/0! = 0.000045

P(k = 1) = (1[tex]0^1[/tex] ×  [tex]e^{-10[/tex])/1! = 0.000454

P(k = 2) = (10² ×  [tex]e^{-10[/tex])/2! = 0.00227

P(k = 3) = (10³ ×  [tex]e^{-10[/tex])/3! = 0.007567

P(k = 4) = (1[tex]0^4[/tex] ×  [tex]e^{-10[/tex])/4! = 0.018917

P(k = 5) = (1[tex]0^5[/tex] ×  [tex]e^{-10[/tex])/5! = 0.037833

P(k = 6) = (1[tex]0^6[/tex] ×  [tex]e^{-10[/tex])/6! = 0.063055

P(k = 7) = (1[tex]0^7[/tex] ×  [tex]e^{-10[/tex])/7! = 0.090079

P(k = 8) = (1[tex]0^8[/tex] ×  [tex]e^{-10[/tex])/8! = 0.112599

P(k = 9) = (1[tex]0^9[/tex] ×  [tex]e^{-10[/tex])/9! = 0.12511

P(k = 10) = (1[tex]0^{10[/tex] ×  [tex]e^{-10[/tex])/10! = 0.12511

P(k = 11) = (1[tex]0^{11[/tex] ×  [tex]e^{-10[/tex])/11! = 0.113736

The probability that more than 11 loads occur during a 4-year period is then given by the following Express

1 - [P(k = 0) + P(k = 1) + P(k = 2) + . . . + P(k = 11)]

substitute the values in the above equation, we get

= 1 - [0.000045 + 0.000454 + 0.00227 + 0.007567 + 0.018917 + 0.037833 + 0.063055 + 0.090079 + 0.112599 + 0.12511+ 0.12511 + 0.113736]

simplifying the equation, we get

= 1 - 0.571665 = 0.428335

C. How long must a time period be so that the probability of no loads occurring during that period is at most 0.3

(λ^0 * e^-λ)/0! = 0.3

⇒ e^-λ/1 = 0.3

simplifying the above equation, we get

⇒ e^-λ = 0.3

⇒ -λ = ln 0.3

⇒ -λ = -1.204

⇒ λ = 1.204

The time period = 4 years / 1.204

Time period = 3.2 years

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Remember that the slope-intercept equation of the line is:

where 'm' is the slope and b is the y-intercept.

In this case, we have the following:

therefore,, the slope is m = 2

Answer: 18 combinations

Step-by-step explanation: you want to multiply the amount of ice cream flavors by the amount of children to be able to find the amount of possible combinations. so, 6 children x 3 flavors of ice cream = 18 different combinations. 6 x 3 = 18

The most appropriate choice for surds will be given by-

[tex]-11\sqrt{3}[/tex] is the correct answer.

What are surds?

There are some natural numbers which are not perfect squares. Their square root are not natural numbers. Those numbers are called surds. The most important method for simplification of surds is prime factorization.

[tex]10\sqrt{3} - 4 \sqrt{48}-\sqrt{75}\\10\sqrt{3} - 4\sqrt{2\times2\times 2\times 2\times3}-\sqrt{3\times 5\times5}\\10\sqrt{3} - 4\times 2\times 2\sqrt{3} - 5\sqrt{3}\\10\sqrt{3} - 16\sqrt{3}-5\sqrt{3}\\-6\sqrt{3} - 5\sqrt{3}\\-11\sqrt{3}[/tex]

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Answer:

p = 20

Step-by-step explanation:

7 + 3(p - 1) = 64 ( subtract 7 from both sides )

3(p - 1) = 57 ( divide both sides by 3 )

p - 1 = 19 ( add 1 to both sides )

p = 20

Which graph shows the circle whose equation is (x−1)2+(y+3)2=16?

circle formula:

[tex](x-h)^{2} +(y-k)^{2} =r^{2}[/tex]

Given:

[tex](x-1)^{2} +(y+3)^{2} =4^{2}[/tex]

put into circle formal format:

[tex](x-h)^{2} +(y-k)^{2} =r^{2}\\(x-1)^{2} +(y-(-3))^{2} =4^{2}[/tex]

The center of the circle is at point (h,k)

[tex](x-1)^{2} +(y+3)^{2} =4^{2}[/tex]

center should be at:  (1,-3)

Answer:

lower row, left grid.

Answer:

Lower left, bottm, circle

Step-by-step explanation:

See attached graph

Using a quadratic function, it is found that:

a) The coordinates of the second x-intercept are: (50,0).

b) The vertex shows the maximum flight of the projectile.

c) The coordinates of the vertex are (25, 62).

3) The graph of the equation y = -0.0992(x² - 50x) is given at the end of the answer.

A quadratic function has two x-intercepts, x' and x'', and is defined as follows:

y = a(x - x')(x - x'').

The intercepts are given as follows:

The vertex is found as follows:

Hence the coordinates are: (25, 62).

The equation can be defined as follows:

y = ax(x - 50)

y = a(x² - 50x).

When x = 25, y = 62, hence the leading coefficient is found as follows:

62 = a(25² - 50(25))

-625a = 62

a = -62/625

a = -0.0992.

Hence the equation is:

y = -0.0992(x² - 50x).

The domain of the function is between the roots, hence 0 ≤ x ≤ 50, and the graph is sketched at the end of the answer.

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The given pair of lines are parallel lines.

So, graph the lines on the given equation:

(Refer to the graph attached below)

We can easily look at the graph and tell that the given lines of the equations are parallel to each other.

Therefore, the given pair of lines are parallel lines.

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Answer:

chad's other friend picked up 1 3/8 pounds of berries

Step-by-step explanation:

chad = 2 1/2 = 2 4/8

friend 1 = 1 3/8

2 4/8 + 1 3/8 = 3 7/8

5 1/4 = 5 2/8

5 2/8 - 3 7/8 = 1 3/8

Answer:

I agree with your answer.

Step-by-step explanation:

The value of f¹(x) = x/5

What is function?

A function in maths is a special relationship among the inputs (i.e. the domain) and their outputs (known as the codomain) where each input has exactly one output, and the output can be traced back to its input.

We are given f(x) = 5x

and we are to find inverse of f(x).

Replace f(x) by y.

So,

y = 5x

Isolate x

x = y/5

Replace x by f'(y)

So,

f'(y) = y/5

Replace all occurrences of y by x.

So,

f'(x) = x/5

Therefore, the inverse of function f(x) = 5x is f'(x) = x/5

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Answer:

y=5

Step-by-step explanation:

RS  +    ST   =    RT

9y+2     +     2y+3       =   60

11y         +      5         = 60

11y   =     55

Y = 5

The sum of  -1 (3/4) and 2 (1/2) is the same as the difference between 2 (1/2) and 1 (3/4).

Firstly, we will convert the mixed fractions into improper fractions.

-1 and 3/4 = -7/4

2 and 1/2 = 5/2

Addition of -1 (3/4) and 2 (1/2) = -7/4 + 5/2 = -7/4 + 10/4 = 3/4

Difference between  2 and 1/2 and 1 and 3/4 = 5/2 - 7/4 = 10/4 - 7/4 = 3/4

As both the values equal to 3/4 , we can say that the addition of  -1  and 3/4 and 2 and 1/2 is the same as the difference between 2 and 1/2 and 1 and 3/4.

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The total money spent on fruits is $7.03

While at  the fruit stand, Ramon bought the following fruits,

3 pounds of apples that cost $0.89 per pound

4 cantaloupes that each cost $1.09

So, the total amount he spent on the materials he bought without including taxes is,

Total money spent = 3 x ( 0.89 ) + 4 x ( 1.09 )

                                = 2.67 + 4.36

                                = 7.03

The total money spent on fruits is $7.03

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Answer: [tex]f(1)=1, f(2)=0, f(3)=2[/tex]

Step-by-step explanation:

[tex]0 \leq 0 \leq 1 \implies f(1)=1^2 =1\\\\1 < 1 \leq 2 \implies f(2)=-2+2=0\\\\2 < 3 \leq 3 \implies f(3)=3^2 -3(3)+2=2[/tex]