When someone hits a wooden board, what is the action force? What is the reaction force?

Answer:

Heat flows from hot to cold objects. When a hot and a cold body are in thermal contact, they exchange heat energy until they reach thermal equilibrium, with the hot body cooling down and the cold body warming up. This is a natural phenomenon we experience all the time.

Explanation:

The term cause and effect relationship relates to a situation where an effect is directly traceable to a cause.

The term cause and effect relationship relates to a situation where an effect is directly traceable to a cause. The question is incomplete and the article was not mentioned.

A typical example of cause and effect relationship is that increased fossil  fuel use is leading to a rise in the average temperature of the planet.

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Answer:

Approximately [tex]1.1 \times 10^{4}\; {\rm Pa}[/tex] and [tex]8.0 \times 10^{3}\; {\rm Pa}[/tex], respectively (assuming that [tex]g = 9.81\; {\rm N \cdot kg^{-1}}[/tex].)

The [tex]55.5\; {\rm kg}[/tex] box exerts more pressure than the [tex]65.5\; {\rm kg}[/tex] box.

Explanation:

Let [tex]m[/tex] denote the mass of the [tex]55.5\; {\rm kg}[/tex] box.

The weight of that box would be: [tex]W = m\, g[/tex].

The normal force [tex]N[/tex] that this box exerts on the ground would be the same as its weight: [tex]N = W = m\, g[/tex].

If the contact area between the box and the ground is [tex]A[/tex], the pressure [tex]P[/tex] that this box exerts on the ground would be [tex]N / A[/tex]. That is:

[tex]\displaystyle P = \frac{N}{A}= \frac{m\, g}{A}[/tex].

The contact area between the ground and this [tex]55.5\; {\rm kg}[/tex] box is [tex]A = 0.25\; {\rm m} \times 0.20\; {\rm m}[/tex]. Substitute in these values and evaluate to find the pressure:

[tex]\begin{aligned} P &= \frac{N}{A} \\ &= \frac{m\, g}{A} \\ &= \frac{55.5\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}}}{0.25\; {\rm m} \times 0.20\; {\rm m}} \\ & \approx 1.1 \times 10^{4}\; {\rm Pa}\end{aligned}[/tex].

Similarly, for the [tex]65.5\; {\rm kg}[/tex] box:

[tex]\begin{aligned} P &= \frac{N}{A} \\ &= \frac{m\, g}{A} \\ &= \frac{65.5\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}}}{0.20\; {\rm m} \times 0.40\; {\rm m}} \\ & \approx 8.0 \times 10^{3}\; {\rm Pa}\end{aligned}[/tex].

Thus, the [tex]55.5\; {\rm kg}[/tex] box exerts greater pressure on the ground than the [tex]65.5\; {\rm kg}[/tex] box.

Answer:

I can't read the questions they aren't in the photo

Answer:

Friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. There are several types of friction: Dry friction is a force that opposes the relative lateral motion of two solid surfaces in contact.

Coefficient of friction, ratio of the frictional force resisting the motion of two surfaces in contact to the normal force pressing the two surfaces together. It is usually symbolized by the Greek letter mu (μ). Mathematically, μ = F/N, where F is the frictional force and N is the normal force.

Answer:

initial KE = final PE

1/2 m v^2 = m g h

h = v^2 / (2 * g) = 3.2^2 / (2 * 9.8) = .52 m    height of ramp

Answer:

there is friction between the soccer ball and the table.

Explanation:

there is a friction between the table and the ball the friction opposing motion.there is reaction and action force a frictional force which acts against motion.

Answer:

B. bc I used it worked for me >:>

Explanation:

An object which moves 10 km in 30 minutes .

we have to find the average speed of the object .

Changing unit of time into hour

Time = 30/60 hour

Time = 1/2 hour

Time = 0.5 hour

Now let's calculate the average speed

[tex] \rm\bf \: Average \: speed \: = \frac{Total \: distance}{Total \: time \: } [/tex]

Put the value we get

[tex] \dashrightarrow \sf \: Average \: speed \: = \frac{10}{0.5} \\ \\ \dashrightarrow \sf \: Average \: speed \: = \frac{100}{5} \\ \\ \dashrightarrow \sf \: Average \: speed \: = \cancel \frac{100}{5} \\ \\ \dashrightarrow \sf \: Average \: speed \: =20km {hr}^{ - 1} [/tex]

So, the average speed is 20km/hr

Answer: A watt unit is equal to 1 joule/sec.

Explanation:  So you have a lightbulb with 50% efficiency, so it turns half the energy it consumes into light energy.

5 answers

They realized this as result of the number of sunspots getting larger and smaller over the course of the years .

This is defined as a temporary phenomena on the Sun's photosphere that appear as spots darker than the surrounding areas.

The presence of these sunspots is what gave Astronomers the idea of the Sun having varying levels of activities over the years.

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The potential across the capacitor at t = 1.0 seconds, 5.0 seconds, 20.0 seconds respectively is mathematically given as

Question Parameters:

A 1. 0 μf capacitor is being charged by a 9. 0 v battery through a 10 mω resistor.

at

Generally, the equation for the Voltage is mathematically given as

v(t)=Vmax=(i-e^{-t/t})

Therefore

For t=1

V=5(i-e^{-1/10})

t=0.476v

For t=5s

V2=5(i-e^{-5/10})

t=1.967

For t=20s

V2=5(i-e^{-20/10})

V2=4.323v

Therefore, the values of voltages at the various times are

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Complete Question

A 1.0 μF capacitor is being charged by a 5.0 V battery through a 10 MΩ resistor.

Determine the potential across the capacitor when t = 1.0 seconds, 5.0 seconds, 20.0 seconds.

The value of the electric force acting on the charge will be 0.9 N.The electric force is the product of the charge and the electric field strength.

What is electric force?

The electric force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.

The given data in the problem is;

q is the  charge = 4. 5 × 10⁻⁵ C

E is the electric field strength.=2.0 ×10⁴

F is the electric force=?

The electric force is given as;

[tex]\rm F = qE \\\\ \rm F = 4.5 \times 10^{-5} \times 2.0 \times 10^4 \\\\ \rm F =0.9 \ N[/tex]

Hence the value of the electric force acting on the charge will be 0.9 N.

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The radius of the track in the circular motion is 0.164 mm.

The magnetic force of the charge is calculated as follows;

F = qvB

The centripetal force experienced by the charge is calculated as follows;

[tex]F = \frac{mv^2}{r}[/tex]

[tex]qvB = \frac{mv^2}{r} \\\\qB = \frac{mv}{r} \\\\r = \frac{mv}{qB} \\\\[/tex]

The radius of the track is calculated as follows;

[tex]r = \frac{9.1 \times 10^{-31} \times 5.5 \times 10^6}{1.6 \times 10^{-19} \times 0.19} \\\\r = 1.64 \times 10^{-4} \ m\\\\r = 0.164 \times 10^{-3} \ m\\\\r = 0.164 \ mm[/tex]

Thus, the radius of the track in the circular motion is 0.164 mm.

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Answer:

csggggresdd

...........

Answer:

yes :)

Explanation:

The late collisions would be observed on the half-duplex end of this type of connection. It occurs when a connection there are two duplex formats.

A duplex mode is a type of Ethernet network capable of sending and receiving data simultaneously.

A duplex connection device is an approach in which point-to-point connection data are transmitted in both directions.

In a duplex connection, data are transmitted at the same time simultaneously (duplex) and/or in one direction at each time (half-duplex).

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Answer:

b

Explanation:

because it has the biggest number

Answer:

there are some ups and downs in life and particle is describing it as a result of happiness

Ф = E S is the total flux

Assuming the charge is at the origin-

The flux will be the same for all sides

The total area is 6 m^2

Ф = 6 * 1 N-m^2 / C = 6 N-m^2 / C

The total charge in the box is then 6 C (oulombs)

(Remember F = Newtons = E Q so E is in N/C

Answer:

11-false

12-false

13-false

14-false

15-false

Explanation:

11- Magnets only attract metal

12- They will repel not pull together

13- The magnet on the horseshoe is only magnetic to the hoof

14-Two opposites on a magnet will attract  eachother

15-NOOO

Answer:

[13,101 RPM]

[1372 rad/s]

Explanation:

Answer:

The magnetic field strength of an electromagnet is therefore determined by the ampere-turns of the coil with the more turns of wire in the coil the greater will be the strength of the magnetic field

Explanation:

Answer:

20g/ml

Explanation:

the mass must be in gram and 90-60 =30

so 600g/30ml =20g/ml

Answer:

Measurement is called the process of finding exact quantity of a substances.

at the same distance behind the mirror

Heat always transfers from substances with high thermal energy to substances with low thermal until both substances reach the maximum temperature

Explanation:

9 × 10^-3 × 13.59 = 0.122 N

The given question is incorrect I think the question you asking is:

A particle with a charge of +7.4μC is separated from another charged particle with a charge of -3.6μC by a distance of 1.4 m. Find the direction and the magnitude of the electrostatic force between the particles.

The electrostatic force between the particles is 0.122N. The direction of the force is from the negatively charged particle to the positively charged particle.

The electrostatic force is the force of attraction or repulsion between two charged particles due to their electric charges. It is a fundamental force in nature and is described by Coulomb's law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

Here in the Question,

Given Data:

Charge of particle 1 (q1) = +7.4 μC = 7.4 × 10^-6 C

Charge of particle 2 (q2) = -3.6 μC = -3.6 × 10^-6 C

Distance between the two particles (r) = 1.4 m

Coulomb's constant (k) = 8.99 × 10^9 N·m^2/C^2

Using Coulomb's law:

Electrostatic force (F) = (k * |q1| * |q2|) / r^2

where |q1| and |q2| are the magnitudes of the charges.

Substituting the values, we get:

F = (8.99 × 10^9 N·m^2/C^2) * (7.4 × 10^-6 C) * (3.6 × 10^-6 C) / (1.4 m)^2

F = 0.12219≈0.122

Therefore, The electrostatic force between the particles is 0.122N. Since one of the charges is negative, the force will be attractive, pulling the particles toward each other.

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Answer: The answer is B. 150.002

Explanation: Add 0.0020 by 150

Force on a 0.0020 C charge in an electric field of 150 V/m will be 0.3 N

An electric field is defined as the electric force per unit charge . The electric field is radially outward from a positive charge and radially in toward a negative charge .

General formula to find Electric field is :

Electric field  = Force / charge

given

charge = 0.0020 C

Electric field = 150 V/m

Force = ?

Force  = Electric field * charge

          =  150 V/m * 0.0020 C

          = 0.3 N

Force on a 0.0020 C charge in an electric field of 150 V/m will be 0.3 N

correct answer is A) 0.30 N

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