Which of the following shows the division problem down below

Which Of The Following Shows The Division Problem Down Below

Answers

Answer 1

Question:

Solution:

Synthetic division is a quick method of dividing polynomials; it can be used when the divisor is of the form x-c. In synthetic division, we write only the essential parts of the long division. Notice that the long division of the given problem is written as:

thus, the synthetic division of the given problem would be:

Writing 6 instead of -6 allows us to add instead of subtracting. We can conclude that the correct answer is:

A.

Which Of The Following Shows The Division Problem Down Below
Which Of The Following Shows The Division Problem Down Below
Which Of The Following Shows The Division Problem Down Below

Related Questions

The ages of three siblings, Ben, Bob and Billy, are consecutive integers. The square of the age of the youngest child Ben is four more than eight times the age of the oldest child, Billy. How old are the three boys?

Answers

Let the age of the youngest child (Ben) be x years.

Since the ages are consecutive integers, the ages of the other 2 are (x + 1) and (x + 2).

It was given that the age of the youngest child is four more than eight times the age of the oldest child. This means that:

[tex]x^2-4=8(x+2)[/tex]

We can rearrange the equation above and solve for x as a quadratic equation:

[tex]\begin{gathered} x^2-4=8x+16 \\ x^2-8x-20=0 \end{gathered}[/tex]

Using the factorization method, we have:

[tex]\begin{gathered} x^2-10x+2x-20=0 \\ x(x-10)+2(x-10)=0 \\ (x-10)(x+2)=0 \\ \therefore \\ x-10=0,x+2=0 \\ x=10,x=-2 \end{gathered}[/tex]

Since the age cannot be negative, the age of the youngest child is 10.

Therefore, the ages are:

[tex]\begin{gathered} Ben=10\text{ }years \\ Bob=11\text{ }years \\ Billy=12\text{ }years \end{gathered}[/tex]

The data in the table show how long (in minutes, t) it takes several commuters to drive to work. Find the correlation coefficient and the equation of the best fit for the data. Treat the commute distance d as the independent variable.

Answers

Given the set of data

sort

Commute data (x)

24,25,27,30, 35,35,46,50,52

Commute distance (y)

20,20,29,20,34,39,29,34,50

The line of best fit is given by

with

[tex]R^2=0.5592[/tex][tex]R=\sqrt{0.5592}[/tex][tex]R=0.747[/tex]

R= 0.75

with function

[tex]t=0.7+5.5[/tex]

Correct answer

option D

Answer: r ≈ 0.75

              t ≈ 0.8d + 11.5

Step-by-step explanation:

You have to use a graphing calculator to solve this problem.

This is the correct answer (I just took the test).

8% of the students at Jemerson Middle School are absent because of illness. If there are 150 students in the school, how many are absent? 12015128

Answers

12 students

Explanation

when you have 8% , it means 8 of every 100 students are absent

find the decimal form

[tex]8\text{ \% = }\frac{8}{100}=0.08[/tex]

then, to find the 8% of any number, just multiply the number by 0.08

Step 1

If there are 150 students in the school, how many are absent?

[tex]\begin{gathered} \text{absent}=\text{total}\cdot0.08 \\ \text{absent}=150\cdot0.08 \\ \text{absent}=12 \end{gathered}[/tex]

so, 12 students are absent

Male and female populations of elephantsunder 80 years old are represented by age inthe table below. Completo parts (a) through(d)(a) Approximate the population mean and standard deviation of age for males)(Round to two decimal places as needed.) )

Answers

Solution:

Given:

From the table of values derived above;

The mean for males is;

[tex]\begin{gathered} \bar{x}=\frac{\sum ^{}_{}fx}{n} \\ \bar{x}=\frac{5774.5}{141} \\ \bar{x}=40.95 \end{gathered}[/tex]

The standard deviation is;

Hence,

[tex]\begin{gathered} \sigma=\sqrt[]{\frac{300115.25-\frac{5774.5^2}{141}}{141}} \\ \sigma=\sqrt[]{\frac{300115.25-236488.2996}{141}} \\ \sigma=\sqrt[]{\frac{63626.95035}{141}} \\ \sigma=\sqrt[]{451.25497} \\ \sigma=21.243 \\ \\ To\text{ two decimal places,} \\ \sigma=21.24 \end{gathered}[/tex]

Therefore, the population standard deviation for males is 21.24

Determine whether the statement is true or false, and explain why.
If a function is positive at x = a, then its derivative is also positive at x = a.
Choose the correct answer below.
OA. The statement is true because the sign of the rate of change of a function is the same as the sign of its value.
OB. The statement is false because the derivative gives the rate of change of a function. It expresses slope, not
value.
OC. The statement is false because the sign of the rate of change of a function is opposite the sign of its value.
OD. The statement is true because the derivatives of increasing functions are always positive.

Answers

Answer: B. The statement is false because the derivative gives the rate of change of a function. It expresses slope, not value.

What property of equity is this identify the property : if B is between O and K, BK=OK

Answers

Segment addition

The sum of the lenghts of the segments OB and Bk will give the total lenght OK

Use trigonometry to find QP. Round to the nearest tenth.

Answers

Since this is a right triangle, we can use trig functions

cos theta = adj side/ hypotenuse

cos Q = QP / QR

cos 38 = QP / 25

25 cos 38 = QP

19.70026884= QP

Rounding to the nearest tenth

19.7 = QP

In 3 plays the southside football team drove 10 1/2 yards . How many yards did they average in each day?

Answers

If in three plays southside football team drove [tex]10\frac{1}{2}[/tex] yards, then the number of yard they drove average in each day is [tex]3\frac{1}{2}[/tex] yards

Number matches played by southside football team = 3

Total distance they drove = [tex]10\frac{1}{2}[/tex] yards

Convert the mixed fraction to the simple fraction

[tex]10\frac{1}{2}[/tex] yards = 21/2

Number of yards they drove average in each day = Total distance they drove ÷ Number matches played by southside football team

Substitute the values in the equation

= 21/2 ÷ 3

= 21/2 × (1/3)

= 7/2 yards

Convert the simple fraction to the mixed fraction

7/2 yards = [tex]3\frac{1}{2}[/tex] yards

Hence, if in three plays southside football team drove [tex]10\frac{1}{2}[/tex] yards, then the number of yard they drove average in each day is [tex]3\frac{1}{2}[/tex] yards

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Find the savings plan balance after 6 months with an APR of 8% and monthly payments of $300.

Answers

316.21 is the savings plan balance after 6 months with an APR of 8% and monthly payments of $300.

What is Percentage?

percentage, a relative value indicating hundredth parts of any quantity.

We need to find the savings plan balance after 8 months with an APR of 8% and monthly payments of $300.00.

Let 8% is changed to decimal value by dividing with hundred.

8/100=0.08.

Now we are required to find the growth factor.

growth factor = (1 + (0.08  / 12))   per month   = 1.00667

After 9 months, the balance is

($300.00)*(1.00667)8

316.21 is the balance after 6 months.

Hence 316.21 is the savings plan balance after 6 months with an APR of 8% and monthly payments of $300.

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given g(x)= -12f(x+1)+7 and f(-4)=2 fill in the blanks round answers to 2 decimal points as needed g( )=

Answers

We know the value of f(-4), which is 2

Let's think about a value of x in which we can calculate the value of f(x+1) using the given information (it means x+1 has to be equal to -4)

x+1=-4

x=-4-1

x=-5

Now use this value to calculate g(x)

[tex]\begin{gathered} g(-5)=-12\cdot f(-5+1)+7 \\ g(-5)=-12\cdot f(-4)+7 \end{gathered}[/tex]

As we said, we already know the value of f(-4), use it to calculate g(-5)

[tex]\begin{gathered} g(-5)=-12\cdot2+7 \\ g(-5)=-24+7 \\ g(-5)=17 \end{gathered}[/tex]

Irene is 54 ⅚ inches tall. Theresa is 1 ⅓ inches taller than Irene and Jane is 1 ¼ inches taller than Theresa How tall is Jane

Answers

Let be "n" Irene's height (in inches), "t" Theresa's height (in inches) and "j" Jane's height (in inches).

You know Irene's height:

[tex]n=54\frac{5}{6}[/tex]

You can write the Mixed number as an Improper fraction as following:

- Multiply the Whole number by the denominator.

- Add the product to the numerator.

- Use the same denominator.

Then:

[tex]\begin{gathered} n=\frac{(54)(6)+5}{6}=\frac{324+5}{6}=\frac{329}{6} \\ \end{gathered}[/tex]

Now convert the other Mixed numbers to Improper fractions:

[tex]\begin{gathered} 1\frac{1}{3}=\frac{(1)(3)+1}{3}=\frac{4}{3} \\ \\ 1\frac{1}{4}=\frac{(1)(4)+1}{4}=\frac{5}{4} \end{gathered}[/tex]

Based on the information given in the exercise, you can set up the following equation that represents Theresa's height:

[tex]t=\frac{329}{6}+\frac{4}{3}[/tex]

Adding the fractions, you get:

[tex]t=\frac{337}{6}[/tex]

Now you can set up this equation for Jane's height:

[tex]undefined[/tex]

I need help with this answer can you explain it

Answers

The solution.

The correct answer is y-intercept at (0,1) and decreasing over the interval

[tex]\lbrack-\infty,\infty\rbrack[/tex]

Hence, the correct answer is the last option (option D)

Mark the corresponding with a check to in the boxplease!

Answers

The whole numbers are defined as the positive integers including zero. The whole number does not contain any decimal or fractional part.

An integer is a number with no decimal or fractional part, from the set of negative and positive numbers, including zero.

A rational number is a number that is of the form p/q where p and q are integers and q is not equal to 0.

An irrational number is a type of real number which cannot be represented as a simple fraction.

Real numbers include rational numbers like positive and negative integers, fractions, and irrational numbers. In other words, any number that we can think of, except complex numbers, is a real number.

Therefore,

what is the area of the following Circle R equals 7

Answers

Answer: Area is 153.94

Step-by-step explanation:

Area = π r 2

if cd = 23.19 and BD=176.8 find BC.Round your answer to the nearest tenth

Answers

we have the following:

[tex]BC=BD-CD[/tex]

replacing:

[tex]\begin{gathered} BC=176.8-23.19 \\ BC=153.61 \end{gathered}[/tex]

Therefore, the answer is 153.61 units

Find the length of the rectangle pictured above, if the perimeter is 82 units.

Answers

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(length + width)

From the information given,

width = 16

Perimeter = 82

Thus, we have

82 = 2(length + 16)

By dividing both sides of the equation by 2, we have

82/2 = 2(length + 16)/2

2 cancels out on the right side of the equation. We have

41 = length + 16

length = 41 - 16

length = 25

720÷5 WORK OUT NEEDED

Answers

144

Explanation:[tex]720\text{ }\div\text{ 5}[/tex]

working the division:

The process:

7 ÷ 5 = 1 R 2

add the 2 to the next number: this gives 22

22 ÷ 5 = 4 R 2

add 2 to the next number: this gives 20

20 ÷ 5 = 4 R 0

The result of 720 ÷ 5 = 144

hannah paid 15.79 for a dress that was originally marked 24.99 what js the percent of discount

Answers

The percentage of discount is 37%

Here, we want to calculate the percentage of discount

The first thing we need to do here is to calculate the discount amount

Mathematically, we have this as;

[tex]24.99-15.79\text{ = 9.2}[/tex]

Now, we find the percentage of 24.99 is this discount

We have this as;

[tex]\frac{9.2}{24.99}\text{ }\times100\text{ \% = 36.8\%}[/tex]

The percentage of discount is approximately 37%

3. A student solved an order of operations problem asshown.(2 - 4)2 – 5(6 - 3) + 13(-2)2 - 30 - 3 + 134 - 33 + 13-16What error did this student make? Explain in completesentences. What should the correct answer be?

Answers

Applying PEMDAS

P ----> Parentheses first

E -----> Exponents (Powers and Square Roots, etc.)

MD ----> Multiplication and Division (left-to-right)

AS ----> Addition and Subtraction (left-to-right)

Parentheses first

[tex]\begin{gathered} (2-4)=-2 \\ (6-3)=3 \\ \end{gathered}[/tex]

substitute

[tex]\begin{gathered} (-2)2-5(3)+13 \\ -4-15+13 \\ -4-2 \\ -6 \\ \end{gathered}[/tex]

The student error was misapplication of the comutative property

consider the parent function f(x)=x^2. a. graph y=f(x). b. write an equation for f(1/2x). Then sketch a graph of y=f(1/2x) and describe the transformation. c.write an equation for f(3x). Then sketch a graph of y=f(3x) and describe the transformation.

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

f(x)=x²

f(1/2x) = ?

graph of y=f(1/2x) = ?

Step 02:

b. f(1/2x)

x ===> 1/2x

[tex]f\text{ (1/2 x) = (}\frac{1}{2}x)^2=\frac{1}{4}x^2[/tex]

Step 03:

c. Graph:

We give values to x, and we obtain the values of y.

f(x) = 1/4 x²

e.g.

if x = 4

y = 1/4 (4)² = 1/4 * 16 = 4

That is the solution for b. and c.

Suppose that $250 is deposited into an account that pays 4.5% interest compoundedquarterly. Using A = P(1 +r/n)nt where t is the number of years, r the interestrate as a decimal, and n the number of times interest is compounded per year, find outhow many years it takes (to the nearest whole year) to reach $1000, and type youranswer into the box.

Answers

31 years

Explanation:

We would apply the compound interest forula:

[tex]A=P\mleft(1+\frac{r}{n}\mright)^{nt}[/tex]

A = future amount = $1000

P = principal = $250

r = rate = 4.5% = 0.045

n = compounded quarterly = 4 times

n = 4

t = time = ?

Inserting the values into the formula:

[tex]\begin{gathered} 1000\text{ = 250(1 + }\frac{0.045}{4})^{4\times t} \\ 1000=250(1+0.01125)^{4t} \\ \text{divide through by 250} \\ \frac{1000}{250}=\text{ }(1+0.01125)^{4t} \\ 4\text{ = (1}.01125)^{4t} \end{gathered}[/tex][tex]\begin{gathered} \text{Taking log of both sides:} \\ \log 4=log(1.01125)^{4t} \\ \log 4=4t\lbrack log(1.01125)\rbrack \\ 0.6021\text{ = 4t(}0.0049) \end{gathered}[/tex][tex]\begin{gathered} 0.6021\text{ = }0.0196t \\ \text{divide both sides by 0.0196} \\ \frac{0.6021}{0.0196}=\frac{0.0196t}{0.0196} \\ 30.72\text{ = t} \\ To\text{ the nearest whole number, t = 31 years} \end{gathered}[/tex]

It takes 31 years to reach $1000.

If the ratio of KL to JK is 2.7. and JL = 162, find JK

Answers

KL / JK = 2:7

JL = 162

JK = ?

JL = KL + JK = 162 KL = 2 JK = 7

KL / JK = 2.7

KL = 162 - JK

Substitution

(162 - JK) / JK = 2.7

Solve for JK

162 - JK = 2.7 JK

162 = 2.7 JK + JK

162 = 3.7 JK

JK = 162 / 3.7

JK = 43.8

10(6 + 4) ÷ (2³-7)² =

Answers

Answer:

100

Explanation:

Given the expression

[tex]10\mleft(6+4\mright)\div(2^3-7)^2[/tex]

First, we evaluate the bracket and exponents.

[tex]=10\mleft(10\mright)\div(8-7)^2​[/tex]

This then gives us:

[tex]\begin{gathered} 100\div(1)^2 \\ =100\div1 \\ =100 \end{gathered}[/tex]

The hands of a clock show 11:20. Express the obtuse angle formed by the hour and minute hands in radian measure.

Answers

ANSWER

[tex]2.44\text{ }rad[/tex]

EXPLANATION

First, let us make a sketch of the clock:

We have that for a minute hand:

[tex]1\text{ }min=6\degree[/tex]

For hour hand:

[tex]1\text{ }min=0.5\degree[/tex]

The hour and minute hand have their origin at 12.

At 11:20, the minute hand had moved 20 mins. This means that:

[tex]20\text{ }min=20*6=120\degree[/tex]

The hour hand had moved at 11 (and 20 mins more), which means:

[tex]\begin{gathered} 11*60\text{ }min+20\text{ }min \\ \Rightarrow660\text{ }min+20\text{ }min \\ 680\text{ }min \end{gathered}[/tex]

Hence, in 680 mins:

[tex]\begin{gathered} 680*0.5 \\ \Rightarrow340\degree \end{gathered}[/tex]

Therefore, the angle formed between 11 and 12 at 11:20 is:

[tex]\begin{gathered} 360-340 \\ \Rightarrow20\degree \end{gathered}[/tex]

Hence, the angle formed at 11:20 is:

[tex]\begin{gathered} 120\degree+20\degree \\ 140\degree \end{gathered}[/tex]

Now, let us convert to radians:

[tex]\begin{gathered} 1\degree=\frac{\pi}{180}rad \\ 140\degree=140*\frac{\pi}{180}=2.44\text{ }rad \end{gathered}[/tex]

That is the obtuse angle formed in radians.

You are choosing between two health clubs. Club A offers membership for a fee
of $20 plus a monthly fee of $25. Club B offers membership for a fee of $25
plus a monthly fee of $24. After how many months will the total cost of each
health club be the same? What will be the total cost for each club?

Answers

Let:

x = Number of months

y1 = Total cost for Club A

y2 = Total cost for Club B

a = Fee of Club A per month

b = Fee of Club B per month

c = Initial fee of Club A

d = Initial fee of Club B

so:

[tex]\begin{gathered} y1=ax+c \\ y1=25x+20 \\ -------- \\ y2=bx+d \\ y2=24x+25 \end{gathered}[/tex]

So, the total cost will be the same for:

[tex]\begin{gathered} y1=y2 \\ 25x+20=24x+25 \\ solve_{\text{ }}for_{\text{ }}x\colon \\ 25x-24x=25-20 \\ x=5 \end{gathered}[/tex]

The cost will be the same for the month number 5. And the total cost will be:

[tex]\begin{gathered} y1(5)=25(5)+20=145 \\ y2(5)=24(5)+25=145 \end{gathered}[/tex]

$145

find the width of a newer 48-in TV whose screen has an aspect ratio of 16:9what is the width?

Answers

Answer:

The width of the TV is 41.84-in

Explanations:

The diagonal size of the TV, d= 48 in

The aspect ratio= 16 : 9

The aspect ratio is usually given in form of width : Height

Let the width = w

Let the height = h

The diagram looks like:

[tex]\begin{gathered} \frac{w}{h}=\text{ }\frac{16}{9} \\ h\text{ = }\frac{9w}{16} \end{gathered}[/tex]

Using the Pythagoras theorem:

[tex]\begin{gathered} d^2=h^2+w^2 \\ 48^2\text{ = (}\frac{9w}{16})^2+w^2 \\ 2304\text{ = }\frac{81w^2}{256}+w^2 \\ \text{Multiply through by 256} \\ 589824=81w^2+256w^2 \\ 589824\text{ = }337w^2 \\ w^2\text{ = }\frac{589824}{337} \\ w^2\text{ = 1750.22} \\ w\text{ = }\sqrt[]{1750.22} \\ w\text{ = 41.84 } \end{gathered}[/tex]

The width of the TV is 41.84-in

Hello am just trying to see if I did this right

Answers

Answer

Variable

c = Cost of one bag of chips

Equation

2.50 + 3c = 5.05

Solution

c = Cost of one bag of chips = 0.85 dollars

Explanation

Cost of one juice pouch = 1.25 dollars

Cost of 2 juice pouches = 2(1.25) = 2.50 dollars

Cost of a bag of chips = c dollars

Cost of 3 bags of chips = (3)(c) = (3c) dollars

(Cost of two juice pouches) + (Cost of three bags of chips) = Total Cost

2(1.25) + 3c = 5.05

2.50 + 3c = 5.05

Subtract 2.50 from both sides

2.50 + 3c - 2.50 = 5.05 - 2.50

3c = 2.55

Divide both sides by 3

(3c/3) = (2.55/3)

c = 0.85 dollars

Hope this Helps!!!

Consider the following algebraic expression:7s - 7Step 1 of 2: Identify the first term of the algebraic expression. Indicate whether the term is a variable term or a constant term. For avariable term, identify the variable and the coefficient of the term.

Answers

Given the algebraic expression below

[tex]7s-7[/tex]

The first term of the algebraic expression is

[tex]7s[/tex]

The first term "7s" is a variable term.

The variable of the first term is "s"

The coefficient of the variable term is 7

"∆ABC~∆DEF. The area of ∆ABC is given. Find the area of ∆DEF. Do not lable the final answer."

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

∆ABC~∆DEF

triangle 1:

AC = 10

area = 65 in²

triangle 2:

DF = 20

area = ?

Step 02:

We must apply the rules of similar triangles to find the solution. .

[tex]\frac{triangle\text{ 1 AC}}{\text{triangle 2 DF }}=\frac{triangle\text{ 1 area}}{\text{triangle 2 area}}[/tex][tex]\frac{10}{20}=\frac{65in^2}{triangle\text{ 2 area}}[/tex]

triangle 2 area * 10 = 65 in² * 20

triangle 2 area = (65 in² * 20 ) / 10

= 130 in²

The answer is:

The area of the big triangle is 130 in² .

Simplify 2+^3 ÷ 2- ^3

Answers

Simplifying a fraction

We want to simplify the following expression:

[tex]\frac{2+\sqrt[]{3}}{2-\sqrt[]{3}}[/tex]

This means that we want to "remove" the denominator".

STEP 1

If we observe the denominator:

[tex](2-\sqrt[]{3})[/tex]

If we multiply it by

2 + √3, then

[tex]\begin{gathered} (2-\sqrt[]{3})(2+\sqrt[]{3}) \\ =4-\sqrt[]{3}^2=4-3=1 \end{gathered}[/tex]STEP 2

We know that if we multiply both sides of a fraction by the same number or expression, the fraction will remain the same, then we multiply both sides by 2 + √3:

[tex]\frac{2+\sqrt[]{3}}{2-\sqrt[]{3}}=\frac{(2+\sqrt[]{3})(2+\sqrt[]{3})}{(2-\sqrt[]{3})(2+\sqrt[]{3})}[/tex]

For the denominator, as we analyzed before

[tex](2-\sqrt[]{3})(2+\sqrt[]{3})=1[/tex]

For the denominator:

[tex](2+\sqrt[]{3})(2+\sqrt[]{3})=(2+\sqrt[]{3})^2[/tex]

Then,

[tex]\frac{2+\sqrt[]{3}}{2-\sqrt[]{3}}=\frac{(2+\sqrt[]{3})(2+\sqrt[]{3})}{(2-\sqrt[]{3})(2+\sqrt[]{3})}=\frac{(2+\sqrt[]{3})^2}{1}=(2+\sqrt[]{3})^2[/tex]STEP 3

Now, we can simplify the result:

[tex]\begin{gathered} (2+\sqrt[]{3})^2=(2+\sqrt[]{3})(2+\sqrt[]{3}) \\ =2^2+2\sqrt[]{3}+(\sqrt[]{3})^2+2\sqrt[]{3} \\ =4+4\sqrt[]{3}+3 \\ =7+4\sqrt[]{3} \end{gathered}[/tex]Answer: 7+4√3

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