Answer:
The answer is "[tex]30.83 \ kip-in[/tex]"
Explanation:
[tex]\to D.L = 50 \ \frac{ lbs}{ft} \\\\\to L.L = 60\ \frac{ lbs}{ft}\\\\[/tex]
Factered load [tex]w_u= 1.2 D.L+1.6 \ D.L[/tex]
[tex]= 1.2 \times 50 +1.6\times 60\\\\= 60 +96\\\\=156 \ \frac{ lbs}{ft}\\\\= 131 \frac{ lbs}{in}\\\\[/tex]
[tex]A= bd= 2\times 10 = 20 \ in^2\\\\Z= \frac{bd^2}{6} =\frac{2\times10^2}{6}= 33.33 \ in^3 \\\\L= 15 \ ft = 180 \ inch[/tex]
bending strength[tex]= f_b =925 \ psi[/tex]
shear strength[tex]= f_v = 120 \ psi[/tex]
movment strength [tex]m_h= z \times f_b[/tex]
[tex]= 33.33 \times 925\\\\ = 20830.25 \ lb-in \\\\ = 30.83 \ kip-in[/tex]
Seperate real and imaginary parts tan(2x+i3y)
Answer:
First you have to separate real and imaginary parts of Tan(x+iy)=Tan(z)=sin(z)/cos(z)
sinz=sin(x+iy)=sinxcos(iy)+cosxsin(iy)=sinxcoshy-icosx sinhy
cosz=cos(x+iy)=cosxcos(iy)-sinxsin(iy)=cosxcoshy−isinxsinhy
Now if you plug in Tan(z) and simplify (it is easy!) you get
Tan(z)=(sin(2x)+isinh(2y))/(cos(2x)+cosh(2y))= A+iB.
This means that
A=sin(2x)/(cos(2x)+cosh(2y)) and B= sinh(2y)/(cos(2x)+cosh(2y))
Now,
A/B=sin(2x)/sinh(2y)
If any questions, let me know.
Briefly discuss the principle forms of communication that might be utilized in the construction industry?
Answer:
xcvjchjcnjkkhjmklk heyyyy biiiiiiiittcccchhh
