The dotted plot representing how much a customer spends in a store from the attached diagram is Option D.
Step 1: Write out the frequency distribution of the population in tabular form
x | f
------------------------------------------
5 | 17
------------------------------------------
| 17
------------------------------------------
I just need help finding the area of shape c.
We need to find the area of Shape C.
Please have a look at the diagram below:
To find x, we can use the Pythagorean Theorem on the right triangle.
[tex]\begin{gathered} 100^2+x^2=107^2 \\ \end{gathered}[/tex]Now, let's solve for x. The steps are shown below:
[tex]\begin{gathered} 100^2+x^2=107^2 \\ x^2=107^2-100^2 \\ x^2=11449-10000 \\ x^2=1449 \\ x=\sqrt[]{1449} \\ x=38.07 \end{gathered}[/tex]So, the top part (dotted line) is
[tex]\begin{gathered} x+100+x \\ =38.07+100+38.07 \\ =176.14 \end{gathered}[/tex]Now, we have a trapezoid. Let's find the area of the trapezoid:
[tex]\begin{gathered} A=\frac{1}{2}(b_1+b_2)h \\ A=\frac{1}{2}(100+176.14)(100) \\ A=13,807 \end{gathered}[/tex]Now, we need to subtract the area labeled (K) from the area of the trapezoid found.
--------------------------------------------------------------------------------
Area k is a triangle with side lengths 117, 117, and 176.14. Let's find the area of the triangle. The diagram is shown below:
Now, we will find h, the height of the triangle using Pythagorean Theorem.
[tex]\begin{gathered} 88.07^2+h^2=117^2 \\ h^2=117^2-88.07^2 \\ h^2=5932.6751 \\ h=\sqrt[]{5932.6751} \\ h=77.02 \end{gathered}[/tex]The area of the triangle (region K) is,
[tex]\begin{gathered} A=\frac{1}{2}bh \\ A=\frac{1}{2}(176.14)(77.02) \\ A=6783.15 \end{gathered}[/tex]The area of region C is the area of trapezoid - area of region k (triangle). So, the area is >>>>
[tex]\begin{gathered} A=13,807-6783.15 \\ A=7023.85 \end{gathered}[/tex]Answer7023.85Put the following equation of a line into slope-intercept form, simplifying all fractions.4x + 20y = -180
The equation of a straight line is
y = mx + c
4x + 20y = -180
make 20y the subject of the formula
20y = -180 - 4x
20y = -4x - 180
divide all through by 20
20y/20 = -4x/20 - 180/20
y = -1/5x - 9
The answer is y = -1/5x - 9 where your slope is -1/5 and intercept is -9
G(x) = 1/x^10 g’(x)=
Differentiation - The value of g'(x) = [tex]\frac{1}{10}x^{-9}[/tex].
Apart from integration, differentiation is among the two key ideas in calculus. A technique for determining a function's derivative is differentiation. Mathematicians use a process called differentiation to determine a function's instantaneous rate of change predicated on one of its variables. The most typical illustration is velocity, which is the rate at which a distance changes in relation to time. Finding an antiderivative is the opposite of differentiation. The rate of change of signal with respect to y has been given by dy/dx if x and y are two variables. The general representation of a function's derivative is given by the equation f'(x) = dy/dx, where y = f(x) is any function.
Given that,
G(x) = [tex]\frac{1}{x^{10} }[/tex]
g’(x)=?
g’(x) is the derivative of g(x).
The derivative of [tex]x^{n} = nx^(n-1)[/tex]
[tex]x^{10} = 10x^(10-1)[/tex]
[tex]x^{10}= 10x^9[/tex]
Then,
[tex]\frac{1}{x^{10} }[/tex] = [tex]\frac{1}{10}x^{-9}[/tex]
Hence, The derivative of g(x) is [tex]\frac{1}{x^{10} }[/tex] = [tex]\frac{1}{10}x^{-9}[/tex].
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The lengths of adult males' hands are normally distributed with mean 189 mm and standard deviation is 7.4 mm. Suppose that 15 individuals are randomly chosen. Round all answers to 4 where possible.
a. What is the distribution of ¯x? x¯ ~ N( , )
b. For the group of 15, find the probability that the average hand length is less than 191.
c. Find the first quartile for the average adult male hand length for this sample size.
d. For part b), is the assumption that the distribution is normal necessary? No Yes
Considering the normal distribution and the central limit theorem, it is found that:
a) The distribution is: x¯ ~ N(189, 1.91).
b) The probability that the average hand length is less than 191 is of 0.8531 = 85.31%.
c) The first quartile is of 187.7 mm.
d) The assumption is necessary, as the sample size is less than 30.
Normal Probability DistributionThe z-score of a measure X of a variable that has mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by the rule presented as follows:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score measures how many standard deviations the measure X is above or below the mean of the distribution, depending if the z-score is positive or negative.From the z-score table, the p-value associated with the z-score is found, and it represents the percentile of the measure X in the distribution.By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex]. The mean is the same as the population mean.For sample size less than 30, such as in this problem, the assumption of normality is needed to apply the Central Limit Theorem.The parameters in this problem are given as follows:
[tex]\mu = 189, \sigma = 7.4, n = 15, s = \frac{7.4}{\sqrt{15}} = 1.91[/tex]
Hence the sampling distribution of sample means is classified as follows:
x¯ ~ N(189, 1.91).
The probability that the average hand length is less than 191 is the p-value of Z when X = 191, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem:
[tex]Z = \frac{X - \mu}{s}[/tex]
Z = (191 - 189)/1.91
Z = 1.05
Z = 1.05 has a p-value of 0.8531, which is the probability.
The first quartile of the distribution is X when Z has a p-value of 0.25, so X when Z = -0.675, hence:
[tex]Z = \frac{X - \mu}{s}[/tex]
-0.675 = (X - 189)/1.91
X - 189 = -0.675 x 1.91
X = 187.7 mm.
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Write a sine function that has a midline of 4 , an amplitude of 3 and a period of 2/3
Given a midline of 4, an amplitude of 3 and a period of 2/3 we are asked to write a sine function.
Explanation
The equation of a sine function is given as
[tex]y=Asin(\frac{2\pi x}{T})+B[/tex]Where A is the amplitude, T is the period and B is the midline of the sine function.
Therefore, we will have;
[tex]\begin{gathered} y=3sin(2\pi x\div\frac{2}{3})+4 \\ y=3sin(2\pi x\times\frac{3}{2}_)+4 \\ y=3s\imaginaryI n(3\pi x)+4 \end{gathered}[/tex]Answer:
[tex]y=3s\imaginaryI n(3\pi x)+4[/tex]Use the distributive property to simplify 10 - 5( -3-7m) completely .
Simplify the expression by using the distributive property.
[tex]\begin{gathered} 10-5(-3-7m)=10+(-5)\cdot(-3)+(-5)\cdot(-7m) \\ =10+15+35m \\ =25+35m \end{gathered}[/tex]So answer is 25 + 35m.
what number need to be changed to make a linear function? And what does it have to turn into?
In order to have a linear function, the rate of change needs to be the same in each point
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]For
(-18,2)=(x1,y1)
(-14,4)=(x2,y2)
[tex]m=\frac{4-2}{-14+18}=\frac{1}{2}[/tex]for
(-14,4)=(x1,y1)
(-12,5)=(x2,y2)
[tex]m=\frac{5-4}{-12+14}=\frac{1}{2}[/tex]for
(-12,5)=(x1,y1)
(0,12)=(x2,y2)
[tex]m=\frac{12-5}{0+12}=\frac{7}{12}[/tex]as we can see here are the two numbers so we will obtain the equation in order to know the number that needs to be change
[tex]y=\frac{1}{2}x+11[/tex]therefore if x=0
[tex]y=\frac{1}{2}(0)+11=11[/tex]the number we need to change is 12 and need to be changed for 11
(0,11)
a. The number that needs to be changed in order to create a linear function is 12
b. That number needs to be changed to 11 in order for the function to be linear
fred had a tray of brownies for his birthday. he ate 1/6 of the brownies by himself and his family ate 1/3 of the brownies how many brownies did fred and his family eat altogether
We want to know how many brownmies did Fred and his family eat together.
We will call to the total of the brownies by 1. On this case, after Fred ate 1/3 of the brownies, he will have:
[tex]1-\frac{1}{3}=\frac{3-1}{3}=\frac{2}{3}[/tex]This means that he has left 2/3 of the brownies. After his family ate 1/6 of the brownies:
[tex]\frac{2}{3}-\frac{1}{6}=\frac{4}{6}-\frac{1}{6}=\frac{3}{6}=\frac{1}{2}[/tex]This means they will have left 1/2 of the tray of brownies, and that they ate half of it.
Imagine you are four years old. A rich aunt wants to provide for your future. She hasoffered to do one of two things.Option 1: She would give you $1000.50 a year until you are twenty-one.Option 2: She would give you $1 this year, $2 next year, and so on, doubling the amounteach year until you were 21.If you only received money for ten years, which option would give you the most money?
Given the situation to model the arithmetic and the geometric sequences.
Imagine you are four years old. A rich aunt wants to provide for your future. She has offered to do one of two things.
Option 1: She would give you $1000.50 a year until you are twenty-one.
This option represents the arithmetic sequence
The first term = a = 1000.50
The common difference = d = 1000.50
The general formula will be as follows:
[tex]\begin{gathered} a_n=a+d(n-1) \\ a_n=1000.50+1000.50(n-1) \\ \end{gathered}[/tex]Simplify the expression:
[tex]a_n=1000.50n[/tex]Option 2: She would give you $1 this year, $2 next year, and so on, doubling the amount each year until you were 21.
This option represents the geometric sequence
The first term = a = 1
The common ratio = r = 2/1 = 2
The general formula will be as follows:
[tex]\begin{gathered} a_n=a\cdot r^{n-1} \\ a_n=1\cdot2^{n-1} \end{gathered}[/tex]Now, we will compare the options:
The first term of both options is when you are four years old that n = 1
you only received money for ten years so, n = 10
So, substitute with n = 10 into both formulas:
[tex]\begin{gathered} Option1\rightarrow a_{10}=1000.50(10)=10005 \\ Option2\rightarrow a_{10}=1\cdot2^{10-1}=2^9=512 \end{gathered}[/tex]So, the answer will be:
For ten years, the option that gives the most money = Option 1
Find (and classify) the critical points of the following function and determine if they are local max, local min, or neither: f(x) =2x^3 + 3x^2 - 120x
As given by the question
There are given that the function:
[tex]f(x)=2x^3+3x^2-120x[/tex]Now,
To find the critical point, differentiate the given function with respect to x and put the result of function equal to zero
So,
[tex]\begin{gathered} f(x)=2x^3+3x^2-120x \\ f^{\prime}(x)=6x^2+6x-120 \end{gathered}[/tex]Then,
[tex]\begin{gathered} f^{\prime}(x)=0 \\ 6x^2+6x-120=0 \\ x^2+x-20=0 \\ x^2+5x-4x-20=0 \\ x(x+5)-4(x+5) \\ (x-4)(x+5) \\ x=4,\text{ -5} \end{gathered}[/tex]Now,
To find the y-coordinate, we need to substitute the above value, x = 4, -5, into the function f(x)
So,
First put x = 4 into the given function:
[tex]\begin{gathered} f(x)=2x^3+3x^2-120x \\ f(4)=2(4)^3+3(4)^2-120(4) \\ =128+48-480 \\ =-304 \end{gathered}[/tex]And,
Put x = -5 into the function f(x):
[tex]\begin{gathered} f(x)=2x^3+3x^2-120x \\ f(-5)=2(-5)^3+3(-5)^2-120(-5) \\ =-250+75+600 \\ =425 \end{gathered}[/tex]Hence, the critical point is, (4, -304) and (-5, 425).
Now,
To find the local maxima and local minima, we need to find the second derivative of the given function:;
So,
[tex]\begin{gathered} f^{\prime}(x)=6x^2+6x-120 \\ f^{\doubleprime}(x)=12x+6 \end{gathered}[/tex]Now,
The put the value from critical point into the above function to check whether it is maxima or minima.
So,
First put x = 4 into above function:
[tex]\begin{gathered} f^{\doubleprime}(x)=12x+6 \\ f^{\doubleprime}(4)=12(4)+6 \\ f^{\doubleprime}(4)=48+6 \\ f^{\doubleprime}(4)=54 \\ f^{\doubleprime}(4)>0 \end{gathered}[/tex]And,
Put x = -5 into the above function
[tex]\begin{gathered} f^{\doubleprime}(x)=12x+6 \\ f^{\doubleprime}(-5)=12(-5)+6 \\ f^{\doubleprime}(-5)=-60+6 \\ f^{\doubleprime}(-5)=-54 \\ f^{\doubleprime}(-5)<0 \end{gathered}[/tex]Then,
According to the concept, if f''(x)>0 then it is local minima function and if f''(x)<0, then it is local maxima function
Hence, the given function is local maxima at (-5, 425) and the value is -54 and the given function is local minima at point (4, -304) and the value is 54.
While at college orientation, Kate is buying some cans of juice and some cans of soda for the dorm. The juice is $0.60 per can while the soda is $0.75. Kate has $24 of dorm funds all to be spent. What is an equation that represents all the different combinations of juice and soda Kate can buy for $24 and how many different combinations of drinks are possible?
From the question the following can be derived:
(a)
Let x cans of juice and y cans of soda be purchased for the dorm. Then the cost of the juice and soda is 0.60x + 0.75y. The equation of all the combinations of juice and soda is 0.60x + 0.75y = 24.
(b)
The cost of exactly 24 cans of juice is $24 * 0.60 = $14.40. After this purchase, the remaining sum of money available is $24 - $14.40 = $9.60. This will suffice to buy 12 cans of soda, leaving a balance of $0.80. Thus. the entire money cannot be spent if exactly 24 cans of juice are purchased.
(c)
Below is a graph of the line 0.6x + 0.75y = 24 or 4x + 5y = 160 is plotted. All possible cimbinations of juice and soda will lie on this line. The x-intercept is 40 and the y-intercept is 32. Since neither of x and y can be negative, hence the lower and upper bounds for x are 0 and 40 and the lower ad upper bounds for y are 0 and 32. Also , x has to be multiple of 5 and y has to be a multiple of 4. As may be observed from the graph, only 9 combinations are possible which are (x, y):
(0, 32), (5, 28), (10, 24), (15, 20), (20, 16), (25, 12), (30, 8), (35, 4), (40, 0).
Graph:
(a + 3)-(a + 2) Please help bc im stuck :>
Answer: 1
Step-by-step explanation:
We are given (a + 3) - (a + 2)
To think of this another way, we can distribute the negative sign out into the (a + 2)
(a + 3) -(a) - (2)
Now our expresssion looks like this:
(a + 3) - a - 2
Simplifying, we get
a - a + 3 - 2
The a terms cancel leaving us with
3-2
and that equals
1
Answer:
1
Step-by-step explanation:
1. Rewrite
: (a+3)-(a+2) = a + 3 - a - 2
2. Subtract
: 3-2 = 1 ... so now the equation is a + 1 - a
3. Combine like terms
: a -a = 0 (the a's cancel out) ... now you're left with 1
Since there is nothing left, your answer is 1.
Last year, the numbers of skateboards produced per day at a certain factory were normally distributed with a mean of 20,500 skateboards and a standard deviation of 55 skateboards.
a) 84.13%
b) 2.28%
c) 15.86%
Explanation:Given:
the numbers of skateboards produced per day at a certain factory were normally distributed
mean = 20, 500
standard deviation = 55
To find:
a) On what percent of the day did the factories produced 20,555 or fewer?
b) On what percent of the day did the factories produced 20,610 or fewer?
c) On what percent of the day did the factories produced 20445 or fewer?
To determine the answers, we will use the z-score formula and then use the standard normal table to get the equivalence of the z-score
The formula of score is given as:
[tex]\begin{gathered} z=\frac{X-μ}{σ} \\ \mu\text{ = mean} \\ σ\text{ = standard deviation} \\ =\text{ value we want to find} \end{gathered}[/tex][tex]\begin{gathered} a)\text{ X}=\text{ 20555} \\ z\text{ = }\frac{20555\text{ - 20500}}{55}\text{ } \\ z\text{ = }\frac{55}{55}\text{ = 1} \\ on\text{ the standard normal table, z = 1 gives 0.84134} \\ Percent\text{ that they produced 20555 or fewer = 84.13\%} \end{gathered}[/tex][tex]\begin{gathered} b)\text{ X}=\text{ 20610} \\ z\text{ = }\frac{20610\text{ - 20500}}{55} \\ z\text{ = 2} \\ On\text{ the standard normal table, z = 2 corresponds to 0.97725} \\ \\ In\text{ this case, we were asked for the percent that produce 20610 or more} \\ To\text{ get ths percent, we will subtract 0.97725 from 1} \\ =\text{ 1 - 0.97725 = 0.02275 } \\ percent\text{ that produced 20610 or more = 2.28\%} \end{gathered}[/tex][tex]\begin{gathered} c)\text{ X = 20445} \\ z\text{ = }\frac{20445\text{ - 20500}}{55} \\ z\text{ = -1} \\ This\text{ translate to 0.1586} \\ percent\text{ that produced 20445 or fewer = 15.86\%} \end{gathered}[/tex]The domain and ranger of a linear function is always all real numbers true or false ?
Answer:
Step-by-step explanation:
The domain and range of a linear function is always real numbers (T or F)
It is True. This is because of a couple of reasons.
1.) You cannot divide by 0.
2. A negative number cannot have its square root taken.
The range is determined by the domain in a linear function, and thus it must always consist of real numbers.
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Z2
Find the midpoint m of z₁ = (9+7i) and Z₂ = (-7+7₂).
Express your answer in rectangular form.
m=
Re
The midpoint m of z₁ = (9+7i) and Z₂ = (-7+7i) is 1 + 7i .
Given complex numbers:
[tex]z_{1}[/tex] = (9 + 7i) and [tex]z_{2}[/tex] = (-7 + 7i)
compare these numbers with a1+ib1 and a2+ib2, we get
a1 = 9, a2 = -7 , b1 = 7 and b2 = 7.
Mid point of complex numbers = a1 + a2 /2 + (b1 + b2 /2)i
= (9 + (-7)/2 + (7 + 7 /2)i
= 2/2 + 14/2 i
Mid point m = 1 + 7i
Therefore the midpoint m of z₁ = (9+7i) and Z₂ = (-7+7i) is 1 + 7i
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Cut a 10-foot (ft.) long piece of wood into two pieces so that one piece is 2 ft longer than the other. Which of the following equations depicts the given situation?A. x/2 = 10B. x + 2 = 10C. 2x + 2 = 10D. None of the choices
Given:
Cut a 10-foot (ft.) long piece of wood into two pieces so that one piece is 2 ft longer than the other.
Required:
Which of the following equations depicts the given situation?
Explanation:
Let 10 feet long piece of wood cut into two pieces of length x(smaller piece) and
x+2 larger piece.
So, the equation will be
x + x + 2 =10
2x + 2=10
Answer:
Option C is correct.
You borrow 200 from a friend you repay the loan in two weeks and agreed to pay eight dollars for interest what is the annual percentage rate? Round your answer to the nearest 10th of a percent
one inlet pipe can fill an empty pool in 6 hours and a drain can empty the pool in 15 hours. how long will it take the pipe to fill the pool if the drains left open
The time that it will take the pipe to fill the pool if the drains left open is 10 hours.
How to calculate the value?From the information, one inlet pipe can fill an empty pool in 6 hours and a drain can empty the pool in 15 hours.
The information illustrated that the input pipe gills 1/6 if the pool and the drain empties 1/15 in the pool every hour
The required time taken will be:
= 1/6 - 1/15
= 5/30 - 2/30
= 3/30
= 1/10
Therefore, the time taken is 10 hours.
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find the missing values in the figure below ( I need help as soon as possible only have 5 minutes available)
You can see in the figure attached that there are two Right triangles.
By definition, Right triangles are those triangles that have an angle that measures 90 degrees.
The larger triangle is the triangle ABC, but you only know the lenght of the side BC, which is:
[tex]BC=15m+2.5m=17.5m[/tex]And for the smaller triangle you only know the side whose lenght is 2.5 meters.
Therefore, since the exercise does not provide any other lenght and it does not provide another angle, you can conclude that the missing values cannot be determine with the given information.
So, the answer is OPTION D.
Find the y-intercept and slope of the line below. Then write the equation is slope intercept form (y=mx+b).
The y-intercept is the value of y when x = 0
To identify y-intercept on a graph, we will check for the the value of y when the line crosses the y axis
From the graph, the line crosses the y axis at y = 6
Hence, the y-intercept is 6
To get the slope, we will pick any two points on the line.
Using points (0, 6) and (4, 0)
Applying the slope formula:
[tex]m\text{ = }\frac{y_2-y_1}{x_2-x_1}[/tex][tex]\begin{gathered} x_1=0,y_1=6,x_2=4,y_2\text{ = }0 \\ m\text{ = }\frac{0\text{ - 6}}{4\text{ - 0}} \\ m\text{ = }\frac{-6}{4} \\ m\text{ = slope = -3/2} \end{gathered}[/tex]NOTE: the slope is negative because it is going from up to down (moving downwards)
The equation of slope in intercept form: y = mx + b
m = slope = -3/2
b = y-intercept = 6
The equation in y-intercept becomes:
[tex]y\text{ = }\frac{-3}{2}x\text{ + 6}[/tex]HELP PLEASEEEEE!!!!!!
Answer: D=2/7 R=4/7
Step-by-step explanation: there are 7 parts and D is the 2nd part R is the 4th part.
(CO 6) Find the regression equation for the following data setx 245 187 198 189 176 266 210 255y 50 54 55 78 44 41 51 60cannot be determinedŷ = 74.17x – 0.09ŷ = -0.09x + 74.17ŷ = 0.09x – 74.17
Answer
ŷ = -0.09x + 74.17
Explanation
For the given data set:
x 245 187 198 189 176 266 210 255
y 50 54 55 78 44 41 51 60
The sum of x = 245 + 187 + 198 + 189 + 176 + 266 + 210 + 255 = 1726
The sum of y = 50 + 54 + 55 + 78 + 44 + 41 + 51 + 60 = 433
Mean x = 1726/8 = 215.75
Mean y = 433/8 = 54.125
Sum of squares (SSx) = 8391.5
Sum of products (SP) = -779.75
(Check the table below of the data for a better understanding).
The regression Equation is given by ŷ = bX + a
b = SP/SSx = -779.75/8391.5 = -0.09292
a = My - bMx = 54.13 - (-0.09 x 215.75) = 74.17279
Therefore, the regression equation for the data set is: ŷ = -0.09292x + 74.17279
The correct answer is ŷ = -0.09x + 74.17
y - y1 = m (x - x1 ) write an equation in point slope form given point ( 4, -3 ) and m = 1
The point-slope form of a line is:
y - y1 = m(x - x1)
where (x1, y1) is a point on the line and m is the slope.
Replacing with m = 1 and the point (4, -3):
y - (-3) = 1(x - 4)
y + 3 = x - 4
evaluate the following function for f(-2) .f(x)=3x+12
Given :
[tex]f(x)=3x+12[/tex]WE need to find the value of f(-2)
So, substitute with x = -2
[tex]f(-2)=3\cdot-2+12=-6+12=6[/tex]So, the value of f(-2) = 6
The area of a triangle is 5. two of the sides lengths are 4.1 and 2.5 and the included angle is obtuse. find the measure of the included angle, to the nearest tenth of a degree.
Given data:
The given area of the triangle is A=5.
The first side given is a=4.1.
The second side given is b=2.5.
The expression for the area of triangle is,
[tex]A=\frac{1}{2}ab\sin C[/tex]Substitute the given values in the above expression.
[tex]\begin{gathered} 5=\frac{1}{2}(4.1)(2.5)\text{ sin C} \\ \sin C=0.97561 \\ C=102.7^{\circ} \end{gathered}[/tex]Thus, the value of the angle is 102.7 degrees.
what angle is Supplementary to angle 2 and what are the Verticle angles in this picture?
Suplementary angle = 180° - angle 2
is Angle 1,
because Angle 2 + Angle 1 = 180°
Part 2. Vertical angles are
Angles 2 and 5
Simplify (v2 + 10v + 11)(v2 + 3v – 4) using the distributive property of multiplication ove addition(DPMA)
Given:
[tex](v^2+10v+11)(v^2+3v-4)[/tex]To find- the simplification.
Explanation-
We know that the distribution property of multiplication over addition says
[tex]a(b+c)=ab+ac[/tex]Use this property to simplify, and we get
[tex]\begin{gathered} =(v^2+10v+11)(v^2+3v-4) \\ =v^2(v^2+3v-4)+10v(v^2+3v-4)+11(v^2+3v-4) \end{gathered}[/tex]Multiply by opening the bracket, and we get
[tex]=(v^4+3v^3-4v^2)+(10v^3+30v^2-40v)+(11v^2+33v-44)[/tex]Now, open the bracket and combine the like terms.
[tex]\begin{gathered} =v^4+3v^3-4v^2+10v^3+30v^2-40v+11v^2+33v-44 \\ =v^4+(3v^3+10v^3)+(11v^2-4v^2+30v^2)-40v+33v-44 \end{gathered}[/tex]On further solving, we get
[tex]=v^4+13v^3+37v^2-7v-44[/tex]Thus, from the distributive property of multiplication over addition, we get v⁴+13v³+37v²-7v-44.
The answer is v⁴ + 13v³ + 37v² - 7v - 44.
In a running competition, a bronze, silver and gold medal must be given to the top three girls and top three boys. If 4 boys and 5 girls are competing, how many different ways could the six medals possibly be given out?
ANSWER
1,440
EXPLANATION
We have that 4 boys are competing and also 5 girls are competing. 3 medals are given to the boys and 3 medals are given to the girls.
For the boys, the gold medal can be awarded to one of 4 boys, then the silver medal can be awarded to 3 boys because 1 of them already got the gold medal. Finally, the bronze medal can be awarded to one of 2 boys, since the gold and silver medals are already taken. The number of ways the medals can be given to the boys is,
[tex]permutations_{boys}=4\cdot3\cdot2=24[/tex]This situation is similar for the girls, but in this case, there are 5 girls in total,
[tex]permutations_{girls}=5\times4\times3=60[/tex]The total ways the six medals can be given is,
[tex]permutations_{boys}\times permutations_{girls}=24\times60=1,440[/tex]Hence, there are 1,440 ways to give the six medals to the 4 boys and 5 girls.
decide wether the following sides are acute obtuse or a right triangle.
The acute triangle is defined by the condition,
[tex]a^2+b^2The obtuse triangle is defined by the condition, [tex]a^2+b^2>c^2[/tex]Here, we have,
[tex]\begin{gathered} 19^2=361 \\ 12^2=144 \\ 15^2=225 \\ 12^2+15^2>19^2 \end{gathered}[/tex]Thus, the triangle is an obtuse triangle.
What are all the rational roots of the polynomial f(x) = 20x4 + x3 + 8x² + x - 12?
Answer:
All the rational roots of the polynomial f(x) = 20x4 + x3 + 8x2 + x - 12 are 3/4 and -4/5.