is 2÷2 4 or am I wrong

Answers

Answer 1

2/2 = 1

The answer would be 1


Related Questions

which of the following describes the two spheres A congruentB similarC both congruent and similarD neither congruent nor similar

Answers

The two spheres are similar since they have a proportion of their radius. This proportion is 9/6 (3/2) or 6/9 (2/3).

They are not congruent. They do not have the same radius.

Therefore, the spheres are similar.

Order the following from least to greatest: 0.232, 1.2, 1.09, 0, 3, 0.9

Answers

Answer:

0, 0.232 , 0.9 , 1.09, 1.2 , 3

Admission to a state fair is $10, and each ride ticket costs $2.50. Write an en

Answers

EXPLANATION

Let's call t to the number of tickets and c to the total cost, the appropiate relationship would be:

c = 2.5t + 10

The variable in the expression represents the number of tickets.

(−1/2x+7/10)−(−3/4x−1/5)

Answers

The expression (−1/2x + 7/10) − (−3/4x − 1/5) has a value of  1/4x + 9/10 when simplified

How to evaluate the expression?

From the question, the expression is given as

(−1/2x+7/10)−(−3/4x−1/5)

Rewrite the expression properly to  make it legible

So, we have

(−1/2x + 7/10) − (−3/4x − 1/5)

Expression the above parameter as an equation

This is represented as

(−1/2x + 7/10) − (−3/4x − 1/5) = (−1/2x + 7/10) − (−3/4x − 1/5)

Open the brackets

So, we have the following equation

(−1/2x + 7/10) − (−3/4x − 1/5) = −1/2x + 7/10 + 3/4x + 1/5

Collect the like terms in the equation

(−1/2x + 7/10) − (−3/4x − 1/5) = 3/4x − 1/2x + 7/10  + 1/5

Evaluate

(−1/2x + 7/10) − (−3/4x − 1/5) = 1/4x + 9/10

The expression cannot be further simplified

Hence, the solution to the expression (−1/2x + 7/10) − (−3/4x − 1/5) is 1/4x + 9/10

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question In photograph

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The equation that represents the relationship between x and y in the table is (L.) y = -5x + 3.

What is an Equation in Math?

In mathematics, an equation is a relationship between two expressions that are expressed as equality on each side of the equal to sign.

Given in the table is the relationship between x and y respectively.

Substitute the values of x in the respective equations to find the value of y, the resulting value which matches the value of y in the table determines the correct equation.

J. y = -5x -27

⇒ For x = -3, y = -5(-3) - 27 = 15 -27 = -12 ≠ 18

K. y = -5x + 18

⇒ For x = -3, y = -5(-3) + 18 = 15 + 18 = 33 ≠ 18

L. y = -5x + 3

⇒ For x = -3, y = -5(-3) + 3 = 15 + 3 = 18 ≈ 18

For x = -1, y = -5(-1) + 3 = 5 + 3 = 8

For x = 2, y = -5(2) + 3 = -10 + 3 = -7

For x = 6, y = -5(6) + 3 = -30 + 3 = -27

All the values of x and y in the table satisfy the equation y = -5x + 3. Hence this is the required equation that represents the relationship.

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find the midpoint of PQ. P(6,4) and Q(4,3)

Answers

the midpoint between two points has the following formula

[tex](\frac{x1+x2}{2},\frac{y1+y2}{2})[/tex]

replace in the formula using P as point 1 and Q as point 2

[tex]\begin{gathered} (\frac{6+4}{2},\frac{4+3}{2}) \\ (\frac{10}{2},\frac{7}{2}) \\ (5,\frac{7}{2}) \\ (5,3.5) \end{gathered}[/tex]

Write the complex number in polar form with argument theta between 0 and 2 pie

Answers

[tex]=\text{ 7}\sqrt[]{2}\lbrack cos(tan^{-1}(-1)\text{ + isin}(tan^{-1}(-1)\text{ \rbrack}[/tex]Explanation:[tex]\begin{gathered} let\text{ z = -7 + 7i} \\ r\text{ = }\sqrt[]{(-7)^2+(7)^2} \\ r\text{ = }\sqrt[]{49+49\text{ }}\text{ = }\sqrt[]{98} \\ r\text{ = 7}\sqrt[]{2} \end{gathered}[/tex][tex]\begin{gathered} \tan \text{ }\theta\text{ = }\frac{7}{-7}\text{ = -1} \\ \text{ }\theta=tan^{-1}(-1) \\ \end{gathered}[/tex][tex]\begin{gathered} z\text{= }r(\cos \theta+\text{ isin}\theta) \\ -7\text{ + 7i }=\text{ }r(\cos \theta+\text{ isin}\theta) \\ =\text{ 7}\sqrt[]{2}\lbrack cos(tan^{-1}(-1)\text{ + isin}(tan^{-1}(-1)\text{ \rbrack} \end{gathered}[/tex]

The answer in polar form:

[tex]=\text{ 7}\sqrt[]{2}\lbrack cos(tan^{-1}(-1)\text{ + isin}(tan^{-1}(-1)\text{ \rbrack}[/tex]

The deposits Ginny makes at her bank each month form an arithmetic sequence. The deposit for month 3 is $150, and the deposit for month 5 is %180. Answer the questions below and show all work.1. What is the common difference for the deposits made each month?2. Write an explicit formula for this arithmetic sequence. 3. What is the amount of Ginny's deposit in the 12th month?4. At what month will Ginny first make a deposit that is at least $500?

Answers

SOLUTION

The deposits Ginny makes at her bank each month form an arithmetic sequence. The deposit for month 3 is $150, and the deposit for month 5 is $ 180.

Since it follows an arithmetic sequence, T n = a + ( n- 1 ) d

Month 3 , T 3 = a+ ( 3 - 1 ) d = 150

a + 2 d = 150 --------------------- equ 1

Month 5 , T 5 = a + ( 5 - 1 ) d = 180

a + 4 d = 180 ...........................equ 2

Solving the two equations, we have :

a - a + 4 d - 2 d = 180 - 150

2 d = 30

Divide both sides by 2 , we have:

d = 15

Let us put d = 15 in equ 1 , we have a + 2 d = 150

a + 2 ( 15 ) = 150

a + 30 = 150

a = 150 - 30

a = 120

From the solution,

Month 1 = 120

Month 2 = 120 + 15 = 135

Month 3 = 135 + 15 = 150

Month 4 = 150 + 15 = 165

Month 5 = 165 + 15 = 180

1. What is the common difference for the deposits made each month? d = 15

2. Write an explicit formula for this arithmetic sequence.

Recall that Tn = a + ( n - 1 ) d

Tn = 120 + ( n - 1 ) 15

Tn = 120 + 15 n - 15

Tn = 120 - 15 + 5n

Tn = 105 + 15n

3. What is the amount of Ginny's deposit in the 12th month?

Tn = 105 + 15n

T 12 = 105 + 15 ( 12 )

T 12 = 105 + 180 = 285

4. At what month will Ginny first make a deposit that is at least $500?​

Using Tn = 105 + 15 n = 500

105 + 15 n = 500

15 n = 500 - 105

15 n = 395

Divide both sides by 15 , we have :

n = 26 . 33

n = 27

Let a represent the row number in this pattern. Write a rule that tells you the number of dots, d, in row n (Hint: Your rule should begin with "d=") Row 1 Row 2 Row 3 Row 4​

Answers

The rule to show the number of dots in the pattern is

d = 2a

What is a pattern?

A pattern is a repetition of items, when the repetition is in ordered then the pattern can be forecasted.

The given pattern is ordered by the rule at which it was formed. The rule helps to forecast the number of dots in the next row

How to get the rules of the pattern

The information given in the question include:

Let a represent the row number in this patternA picture image shoeing the rows and dotsYour rule should begin with "d="

row 1 = 2 dots

row 2 = 4 dots

row 3 = 6 dots

it can be seen that

2 * number of rows  = number of dots

Hence:

d = 2 * a

d = 2a

checking the rule for the 4th row

d = 2 * 4

d = 8

counting the dots confirms the rule is okay

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16 1 point
Triangle congruence SSS is being shown?
True
False
|||
+||

Answers

Answer:

True

Step-by-step explanation:

SSS is being shown because the two sides are known by congruence marks, and the third side is known because it is equal--the two triangles are sharing it.

please help this is very difficult

Answers

Answer:

x=-6. y=6. xy=-36

x=-2. y=-3. xy=6

x=1. y=2. xy=2

Plot Points & Graph Function (Table Given)

Answers

We have the next function

[tex]y=-\sqrt[]{x}+3[/tex]

We need to calculate some points

x y

0 3

1 2

4 1

9 0

Let's plot the points and then we connect them in order to obtain the graph

Angel Corporation produces calculators selling for $25.99. Its unit cost is $18.95. Assuming a fixed cost of $80,960, what is the breakeven point in units?

Answers

The breakeven point of Angel Corporation equals to 11,500 units.

How do we get the breakeven point?

Given that the unit price is $25.99, so if they sell a x units, then, the revenue is: R(x) = $25.99*x

Given that the cost per unit is $18.95, plus a fixed cost of $80,960, then, the cost of x units is: C(x) = $80,960 + $18.95*x

Now, the breakeven point is a  value of x such that the cost is equal to the revenue, so we need to solve:

$25.99*x = $80,960 + $18.95*x

$25.99*x - $18.95*x =  $80,960

$7.04*x =  $80,960

x = $80,960/$7.04

x = 11,500 units

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copy and complete each problem
/20 = 11/55

Answers

Answer:

[tex]\frac{4}{20}[/tex] = [tex]\frac{11}{55}[/tex]

Step-by-step explanation:

[tex]\frac{x}{20}[/tex] = [tex]\frac{11}{55}[/tex]  cross multiply and solve for x

55x = 11(22)

55x = 220  Divide both sides by 55

x = 4

Brianna's teacher asks her if these two expressions 3x + 5 and 4x are equivalent.Brianna says the expressions are equivalent because the value of each expression is 20 when x = 5.Is Brianna correct synlainthink ASAP please

Answers

Step 1

Given data

Expression 1 = 3x + 5

Expression 2 =

Which graph represents an exponential function

This is algebra two graphing exponential functions

Answers

Answer: The Curved Line on Top

Step-by-step explanation: A positive-valued function of a real variable. So the top one

Just learned about this in Algebra 1 about 4 days ago.

A bridge AB is to be built across a river. The point C is located 62m from B, and angle A is 80 degrees, angle C is 60 degrees. How long is the bridge

Answers

The points A, B, and C form a triangle.

From the given information in the question, the triangle ABC can be drawn to have the following parameters:

Recall the Sine Rule. Applied to the triangle above, the rule is stated as follows:

[tex]\frac{BC}{\sin A}=\frac{AC}{\sin B}=\frac{AB}{\sin C}[/tex]

The length of the bridge is AB. Given that the measures of angles A and C, and side BC are known, the following ratio is used to solve:

[tex]\frac{BC}{\sin A}=\frac{AB}{\sin C}[/tex]

Substituting known values, the length of AB is calculated as follows:

[tex]\begin{gathered} \frac{62}{\sin80}=\frac{AB}{\sin60} \\ AB=\frac{62\times\sin60}{\sin80} \\ AB=54.52 \end{gathered}[/tex]

The bridge is 54.52 m long.

Quadratic Factoring: Demonstrate solving some quadraticequations using the following methods: factoring, taking theroot, and completing the square.

Answers

The Solution:

Let's solve with the Factoring Method:

[tex]x^2-x-6=0[/tex][tex]\begin{gathered} x^2-3x+2x-6=0 \\ x(x-3)+2(x-3)=0 \\ (x+2)(x-3)=0 \end{gathered}[/tex][tex]\begin{gathered} x+2=0\text{ or }x-3=0 \\ x=-2\text{ or }x=3 \end{gathered}[/tex]

Solving by the Completing the Square:

[tex]\begin{gathered} x^2-x=6 \\ x^2-x+(\frac{1}{2})^2=6+\frac{1}{4} \\ \\ (x-\frac{1}{2})^2=\frac{25}{4} \end{gathered}[/tex]

Take the square root of both sides.

[tex]\begin{gathered} x-\frac{1}{2}=\sqrt{(\frac{25}{4})} \\ \\ x=\frac{1}{2}\pm\frac{5}{2}=\frac{1\pm5}{2} \end{gathered}[/tex][tex]\begin{gathered} x=\frac{1+5}{2}=\frac{6}{2}=3 \\ \\ \\ x=\frac{1-5}{2}=\frac{-4}{2}=-2 \end{gathered}[/tex]

Therefore, the answers is:

[tex]x=-2\text{ or }x=3[/tex]

how do we do this one there two parts to i t

Answers

Given:

[tex]8\sqrt{y}=x-5y[/tex]

Find: differentiation

Explanation: on differentitaion with respect to x

[tex]\begin{gathered} 8\sqrt{y}=x-5y \\ \frac{8}{2}y^{\frac{-1}{2}}\frac{dy}{dx}=1-5\frac{dy}{dx} \\ 4y^{\frac{-1}{2}}\frac{dy}{dx}+5\frac{dy}{dx}=1 \\ (4y^{\frac{-1}{2}}+5)\frac{dy}{dx}=1 \\ \frac{dy}{dx}=\frac{1}{4y^{\frac{-1}{2}}+5} \end{gathered}[/tex]

[tex]\begin{gathered} \frac{-4}{2}y^{\frac{-3}{2}}\frac{dy}{dx}\frac{d^2y}{dx^2}+5\frac{d^2y}{dx^2} \\ 0=(-2y^{\frac{-3}{2}}\frac{dy}{dx}+5)\frac{d^2y}{dx^2} \\ \frac{d^2y}{dx^2}=0 \end{gathered}[/tex]

put the value of

[tex]\frac{dy}{dx}[/tex]

we get,

[tex]\begin{gathered} (-2\frac{y^{\frac{-3}{2}}}{4y^{\frac{-1}{2}}+5}+5)\frac{d^2y}{dx^2}=0 \\ \frac{d^2y}{dx^2}=0 \end{gathered}[/tex]

Determine whether a tangent line is shown in this figure

Answers

Given:

Required:

To determine whether a tangent line is shown in the given figure.

Explanation:

By the definition of tangent line, we know that tangent line is a straight line that touches the circle at one point.

Now consider the given figure, there is a tangent line in the given figure.

Final Answer:

Yes.

Solve the compound inequality. Graph the solution-7 *x+3<4-The solutions are(Type an inequality or a compound inequality. Sim

Answers

Answer:

[tex]-10\leqslant x<1[/tex]

Explanation:

To solve compound inequalities, we do the same as in an equation or inequality: we need to do the same operation in all places.

We want to solve for x:

[tex]-7\leqslant x+3<4[/tex][tex]-7-3\leqslant x+3-3<4-3[/tex][tex]-10\leqslant x<1[/tex]

And that's the answer

Y=1/3x+2 standard form

Answers

3y - x = 6 is standard form for the given equation

What is standard form of linear equation ?The typical form for linear equations with two variables is Ax+By=C.For instance, the linear equation 2x+3y=5 is in standard form. Finding both intercepts of an equation in this style is quite easy (x and y).This form is also very useful when trying to solve systems of two linear equations.Calculation

y = 1/3x + 2

3y = x + 6

3y - x = 6 is standard form

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Based on the two data sets represented below, complete the following sentences.Options: "greater" or "less"

Answers

We can check that the median of the dataset T is 14, and its mean is also close to 14, while the median of the dataset U is 17 and its mean is close also close to 17. We can also check that the range of the dataset T is 14 and the data is more concentrated at its center, while the range of the dataset U is 20 and the data is more dispersed.

Therefore, we can state that The center of Data Set T is less than the center of Data Set U, and the spread of Data Set T is less than the spread of Data Set U.

The figure below is a trapezoid:10011050mZ1 =m2 =mZ3=Blank 1:Blank 2:Blank 3:

Answers

STEP 1: Identify and Set Up

We have a trapezoid divided by a straight line that divides it assymetrically. We know from the all too famous geometric rule that adjacent angles in a trapezoid are supplementary. Mathematically, we can express thus:

[tex]100^o+<2+<3^{}=180^o=50^o+110^o+<1[/tex]

Hence, from this relation, we can find our unknown angles.

STEP 2: Execute

For <1

[tex]\begin{gathered} 180^o=50^o+110^o+<1 \\ 180^o=160^o+<1 \\ \text{Subtracting 160}^o\text{ from both sides gives} \\ <1=180-120=60^o \end{gathered}[/tex]

<1 = 60 degrees

For <2 & <3

We know from basic geometry that a transversal across two parallel lines gives a pair of alternate angles and as such, <1 = <3 = 60 degrees

We employ our first equation to solve for <2 as seen below:

[tex]\begin{gathered} 100^o+<2+<3^{}=180^o \\ 100^o+<2+60^o=180^o \\ 160^o+<2=180^o \\ \text{Subtracting 160}^{o\text{ }}\text{ from both sides gives:} \\ <2=180-160=20^o \end{gathered}[/tex]

Therefore, <1 = <3 = 60 degrees and <2 = 20

Estimate the time it would take you to drive 278 miles at38 miles per hour. Round to the nearest hour

Answers

Speed formula:

[tex]s=\frac{d}{t}[/tex]

d is the distance

t is the time

As you need to find a time having the distance and speed, solve the equation above for t:

[tex]\begin{gathered} t\cdot s=d \\ t=\frac{d}{s} \end{gathered}[/tex]

Use the given data to find the time:

[tex]\begin{gathered} t=\frac{278mi}{38mi/h} \\ \\ t=7.31h \\ \\ t=7h \end{gathered}[/tex]Then, it would take you 7 hours to drive 278 mi at 38mi/h

Show that (3 * 8 * x)⁷ = 6⁷ * 4⁷ * x⁷

Answers

Answer:

Q.E.D.

Explanation:

Given the expression

[tex](3\times8\times x)^7[/tex]

We want to show that it is equal to the right-hand side.

Now, we note that: 8 = 2 x 4

Substituting 8 = 2 x 4, we have:

[tex]=(3\times2\times4\times x)^7[/tex]

We then go further to get:

[tex]=(6\times4\times x)^7[/tex]

Distributing the exponent, we have:

[tex]=6^7\times4^7\times x^7[/tex]

This is the given right-hand side of the equation as required.

How many triangles can be formed by joining the vertices of a 10-sided polygon?

Answers

The total number of triangles formed by joining vertices of 10-sided polygon is given by the combination of 10 sides taken at 3, i.e. selection of 3 points from 10 points ( because a triangle has 3 vertices). This gives

[tex]10C3=\frac{10!}{3!(10-3)!}=\frac{10!}{3!\cdot7!}=\frac{10\cdot9\cdot8}{6}=\frac{720}{6}=120[/tex]

Then, the answer is the last option: 120

The length of the diagonal of a Rectangle is 14cm,and it forms a 30 degree angle in one corner of the rectangle.What is the area of the rectangle.(A=LxW)Just number 20

Answers

[tex]\text{Area}=84.87(cm^2)[/tex]

Explanation

Step 1

draw the rectangle

here we have a rigth triangle,then

Let

[tex]\begin{gathered} hypotenuse=14 \\ agle=30\text{ \degree} \\ \text{adjacent side= length= l} \end{gathered}[/tex]

so, we need a function that relates those values

[tex]\cos \Theta=\frac{adjacent\text{ side}}{\text{hypotenuse}}[/tex]

replace and solve for length

[tex]\begin{gathered} \cos \Theta=\frac{adjacent\text{ side}}{\text{hypotenuse}} \\ \text{hypotenuse}\cdot\cos \Theta=adjacent\text{ side} \\ 14\text{ cm }\cdot\cos 30=l \\ 12.12435\text{ cm=l} \end{gathered}[/tex]

Step 2

width

similarity, we need a function that relates

[tex]\sin \text{ }\Theta=\frac{opposite\text{ side}}{\text{hypotenuse}}[/tex]

let

[tex]\text{opposite side= width=w}[/tex]

replace and solve for w

[tex]\begin{gathered} \sin \text{ }\Theta=\frac{opposite\text{ side}}{\text{hypotenuse}} \\ \text{hypotenuse}\cdot\sin \Theta=opposite\text{ side} \\ 14\text{ cm }\cdot\sin \text{ 30=w} \\ 7cm=w \end{gathered}[/tex]

Step 3

finally, the area of a rectangle is given by

[tex]\begin{gathered} \text{Area}=\text{ length }\cdot width \\ \text{replacing} \\ \text{Area}=(12.12\cdot7)(cm^2) \\ \text{Area}=84.87(cm^2) \end{gathered}[/tex]

therefore, the answer is

[tex]\text{Area}=84.87(cm^2)[/tex]

I hope this helps you

Correctz is jointly proportional to x and y. If z = 115 when x = 8 and y = 3, find z when x = 5 and y = 2. (Round off your answer to the nearest hundredth.)

Answers

When we have a number that is jointly proportional to two other numebrs, the formula is:

[tex]a=kcb[/tex]

This means "a is jointly proportional to c and b with a factor of k"

Then, we need to find the factor k.

In this case z is jointly proportional to x² and y³

This is:

[tex]z=kx^2y^3[/tex]

Then, we know that z = 115 when x = 8 and y = 3. We can write:

[tex]115=k\cdot8^2\cdot3^3[/tex]

And solve:

[tex]\begin{gathered} 115=k\cdot64\cdot27 \\ 115=k\cdot1728 \\ k=\frac{115}{1728} \end{gathered}[/tex]

NOw we can use k to find the value of z when x = 5 and y = 2

[tex]z=\frac{115}{1728}\cdot5^2\cdot2^3=\frac{115}{1728}\cdot25\cdot8=\frac{2875}{216}\approx13.31[/tex]

To the nearest hundreth, the value of z when x = 5 and y = 2 is 13.31

for each of the following polynomial functions, write the equation of a different polynomial function that has the same key characteristic. explain your thinking.

Answers

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Draw the given graph.

STEP 2: Get the function plotted on the graph.

[tex]undefined[/tex]

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